[英]Replace returns 2 of the same value?
I have a question on why this is happening. 我对为什么会这样有疑问。 First, I'll explain what is going on. 首先,我将解释发生了什么。 I am finding a line in a RichTextBox
and taking a Split
value and replacing it with the same value but with a decimal limit. 我在RichTextBox
找到一行,并取一个Split
值,并将其替换为相同的值但带有十进制限制。 Here is what my file looks like: 这是我的文件的样子:
J6 INT-00113G 227.905 174.994 180 SOIC8
J3 INT-00113G 227.905 203.244 180 SOIC8
U13 EXCLUDES 242.210 181.294 180 QFP128
J6 INT-00113G 227.91227.91 174.99174.99 180 SOIC8
J3 INT-00113G 227.91227.91 203.24203.24 180 SOIC8
U13 EXCLUDES 242.21242.21 181.29181.29 180 QFP128
AND HERE IS MY CODE... WHAT IS THE ERROR TO MAKE IT DO THIS? 这是我的代码...这样做有什么错误?
string[] myLines = placementTwoRichTextBox.Text.Split('\n');
foreach (string line in myLines)
{
// Matches the entire line.
Match theMatch = Regex.Match(line, @".*");
if (theMatch.Success)
{
// Stores the matched value in string output.
string output = theMatch.Value;
// Replaces tabs and extra space with only 1 space delimiter
output = Regex.Replace(output, @"\s+", " ");
// Splits the specified regex into two different regexs.
var componentItem = output.Split(' ');
double d1 = Convert.ToDouble(componentItem[2]);
double d2 = Convert.ToDouble(componentItem[3]);
double round1 = Math.Round(d1, 2, MidpointRounding.AwayFromZero);
double round2 = Math.Round(d2, 2, MidpointRounding.AwayFromZero);
componentItem[2] = Regex.Replace(componentItem[2], @".*", round1.ToString());
componentItem[3] = Regex.Replace(componentItem[3], @".*", round2.ToString());
// Sets the RichTextBox to the string output.
newPl2ItemsRichTextBox.AppendText(componentItem[0] + " " + componentItem[1] + " " + componentItem[2] +
" " + componentItem[3] + " " + componentItem[4] + " " + componentItem[5] + "\n");
}
}
Does anyone know why this is happening? 有人知道为什么会这样吗?
Instead of doing all this, simply do your split, since you know index 2 and 3 contain your numbers... simply do something like: 无需执行所有操作,只需进行拆分即可,因为您知道索引2和3包含数字...只需执行以下操作:
newPl2ItemsRichTextBox.AppendText(componentItem[0] + " " + componentItem[1] + " " + Math.Round(Convert.ToDouble(componentItem[2]), 2) + " " + Math.Round(Convert.ToDouble(componentItem[3]), 2) + " " + componentItem[4] + " " + componentItem[5] + "\\n"); newPl2ItemsRichTextBox.AppendText(componentItem [0] +“” + componentItem [1] +“” + Math.Round(Convert.ToDouble(componentItem [2]),2)+“” + Math.Round(Convert.ToDouble(componentItem [ 3]),2)+“” + componentItem [4] +“” + componentItem [5] +“ \\ n”);
Avoid all the other steps, just split and print. 避免其他所有步骤,只需拆分并打印即可。
Your expression ".*" hits two matches: Try out following code to reproduce: 您的表达式“。*”命中两个匹配项:尝试以下代码重现:
static void Main(string[] args)
{
Regex regex = new Regex(@".*");
MatchCollection matches = regex.Matches(" 227.905 ");
foreach (var match in matches)
{
Console.WriteLine("[{0}]", match);
}
Console.ReadKey();
}
Matches are: " 227.905 " and "" 匹配为:“ 227.905”和“”
回答您的问题:在227.905中,中间有一个点可能使replace函数在227和905上起作用。这就是将舍入的数字插入两次的原因。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.