MySQL选择去年的每个月中有交易的任何部门

Question

Sorry for the specific title, I tied to think of a way to generalize it more but I'm not that knowledgeable - guess that's why I'm asking here...

I've got a table with millions of transactions and one of the columns is the ID of the department that performed that particular transaction:

+-----------------------------------+
| ID | DeptID | Amount |    Date    |
+-----------------------------------+
| 1  |   46   |  4.99  | 2010-01-01 |
+-----------------------------------+
| 2  |   46   |  2.99  | 2010-03-07 |
+-----------------------------------+
| 3  |   57   |  9.99  | 2010-04-04 |
+-----------------------------------+

I want to perform a query that will return any 1 department ID that contains at least 1 transaction for every month in the last year (today is 2011-07-28, I it to start with 2010-08-01 and end with 2011-07-28)

Is there a way to do this without multiple queries?

Answer 1

SELECT DeptID, COUNT(DISTINCT MONTH(`date`)) AS month_count
FROM Transactions
WHERE `date` >= CURDATE() - INTERVAL 1 YEAR
GROUP BY DeptID
HAVING month_count = 12;

Answer 2

我相信您需要在进行交易时更新一列，或者需要有一个包含id，交易时间和交易列的表，其中id是id，交易时间是他们进行交易时的时间，每次交易时交易列都增加1进行创建，然后创建一个查询，其中交易大于或等于1并且交易时间大于或等于当前时间-1年（以秒为单位）

Answer 3

好的，有一个变量，它是当前日期，格式与您现在使用的表中的格式相同，然后在数据库的日期+1年大于等于当前日期的情况下执行此操作，如果不是，则该日期大于一年了