JavaScript样式：不要将包装器对象用于基本类型

Question

In the Google JavaScript style guide, it says not to use wrapper objects for primitive types. It says it's "dangerous" to do so. To prove its point, it uses the example:

var x = new Boolean(false);
if (x) {
  alert('hi');  // Shows 'hi'.
}

OK, I give up. Why is the if code being executed here?

Answer 1

因为每个变量， typeof Object是truthy和包装都是对象。

Answer 2

if(x) will run if x is truthy.

x is truthy if it's not falsey.

x is falsey if x is null , undefined , 0 , "" , false

So since new Boolean(false) is an Object and an Object is truthy, the block runs

Answer 3

In the if(x) case, it's actually evaluating the default Boolean of the object named and not its value of false .

So be careful using Boolean objects instead of Boolean values. =)

Answer 4

The following code uses a Boolean object. The Boolean object is false, yet console.log("Found") still executes because an object is always considered true inside a conditional statement. It doesn't matter that the object represents false; it's an object, so it evaluates to true.

var found = new Boolean(false);
if (found) 
{    console.log("Found");
       // this executes
}