[英]C# generic class accepting a inherited type.
**Preface I'm very new to generics. **序言我对泛型非常陌生。 I have a class I created called Geno.
我创建了一个名为Geno的课程。 My Peno class simply contains a string Name property.
我的Peno类仅包含一个字符串Name属性。 I'm wondering why I cannot call T.Name from within a method on this class.
我想知道为什么我不能从此类的方法中调用T.Name。 How would I access the properties on T?
我将如何访问T上的属性? Any good resources on how this works?
有什么好的资源如何运作?
public class Geno<T> where T : Peno
{
}
public string GetName()
{
return T.Name;
}
Is your Name
property an instance property or a static property? 您的
Name
属性是实例属性还是静态属性? If it's a static property, you don't get polymorphism anyway - you could just call Peno.Name
. 如果它是静态属性,那么无论如何您都不会获得多态性-您可以调用
Peno.Name
。
If it's an instance property, you need an instance on which to call it. 如果它是实例属性,则需要在其上调用它的实例。 For example:
例如:
public class Geno<T> where T : Peno
{
private readonly T value;
public Geno(T value)
{
this.value = value;
}
public string GetName()
{
return value.Name;
}
}
If this doesn't help, please give a more complete example of what you're trying to do. 如果这样做没有帮助,请提供您要尝试执行的操作的更完整示例。
T
is the type Peno
. T
是Peno
类型。 So what you try to do is Peno.Name
, which is probably not what you want. 因此,您尝试做的是
Peno.Name
,这可能不是您想要的。 Something like this would work: 这样的事情会起作用:
public string GetName(T t)
{
return t.Name;
}
Static properties does not support inheritence. 静态属性不支持继承。 Hence you can just call Peno.Name rather than going for T.
因此,您可以只调用Peno.Name而不是T。
If in your case you want to access a normal property, you need to create an instance of T which will let you call its property Name. 如果您要访问常规属性,则需要创建T的实例,该实例将让您将其称为Name。
T is a Generic Type Parameter, not a parameter being passed into the class that is using T. T是泛型类型参数,不是传递给使用T的类的参数。
A Good example of this is List<T>
you say this is a List, which means you are creating a list that contains object of the type of String. 一个很好的例子是
List<T>
您说这是一个列表,这意味着您正在创建一个包含String类型对象的列表。
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