[英]How to get query data using result from another query?
i wanted to get the data from my second query using the first query result. 我想使用第一个查询结果从第二个查询中获取数据。 But i cant What i wanted is to get id from the first query and get content using the id i got. 但是我不能我想要的是从第一个查询中获取ID并使用我获得的ID获取内容。
My 1st query 我的第一个查询
$query = "SELECT book_id , title, SUM(quantity) AS total_sales FROM shopping_cart GROUP BY title ORDER BY total_sales DESC ";
$result = mysqli_query($link, $query) or die(mysqli_error($link)); $ result = mysqli_query($ link,$ query)或die(mysqli_error($ link));
$row = mysqli_fetch_array($result);
2nd query 第二查询
for ($rcount = 0; $rcount < count($row); $rcount++) {
$wanted_id = $result[$rcount]['book_id'];
$query1 = "SELECT * FROM books where id ='$wanted_id' ";
$result1 = mysqli_query($link, $query) or die(mysqli_error($link));
}
i know theres somethign wrong with it but right now i cant seem to figure what how do i do it was wondering if im suppouse to use nested queries. 我知道有一些错误,但现在我似乎无法弄清楚我该怎么做,我想知道我是否支持使用嵌套查询。
EDIT: heres my nested query 编辑:这是我的嵌套查询
$query = "SELECT * from books where id IN (SELECT book_id AS id, title, SUM(quantity) AS total_sales FROM shopping_cart GROUP BY title ORDER BY total_sales DESC )";
i got a "operand should contain 1 column error" tho 我收到“操作数应包含1列错误”的信息
You only need one query, join the books table to your shopping cart table to get the info about each book. 您只需要一个查询,将books表加入购物车表即可获取有关每本书的信息。
SELECT
books.*,
shopping_cart.book_id,
shopping_cart.title,
SUM(shopping_cart.quantity) AS total_sales
FROM
shopping_cart
INNER JOIN
books
ON
shopping_cart.book_id = books.id
GROUP BY
shopping_cart.title
ORDER BY
total_sales DESC
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