简体   繁体   English

比较器使用我班级的 String 字段进行比较?

[英]Comparator using a String field of my class for comparison?

I have a list of objects of type A, and I have to order it for a field of A, which is of type String.我有一个 A 类型的对象列表,我必须为 A 的字段排序,它是 String 类型的。

public class A{
    public String field1;
    public Integer field2;
    ...
}

If I had to order for the int field would have done so:如果我必须订购 int 字段会这样做:

Collections.sort(listOfA, new Comparator<A>() {
        public int compare(A p1, A p2) {
            return p1.field2 - p2.field2);
            }
        });

But unfortunately need to order by the field of type String.但不幸的是需要按字符串类型的字段排序。

How can I do this?我怎样才能做到这一点?

    public int compare(A p1, A p2) {
        return p1.field2.compareTo( p2.field2) );
        }

Alternatively your class could implement interface Comparable , like this或者你的类可以实现接口Comparable ,像这样

public class A implements Comparable<A> {
  public String field1;
  public Integer flied2;

    public int compareTo(A o) {
        return this.field1.compareTo(o.field1);
    }

}

Which would allow you to这将使您能够

Collections.sort(listofA);

Which IMO is preferable/cleaner if A's are always sorted by field1.如果 A 总是按 field1 排序,则哪个 IMO 更可取/更清洁。

你可以使用 String compareTo

Old thread, nevertheless.尽管如此,旧线程。
With java 8, you now have lambdas:使用 Java 8,您现在拥有 lambda:

listOfA.sort((a,b) -> a.field1.compareTo(b.field1));

Also, if one had a getter for field1, which one probably should, you could also then do此外,如果一个人有一个用于 field1 的吸气剂,那一个可能应该,你也可以这样做

listOfA.sort(Comparator.comparing(A::getFieldOne));

If you don't have a getter, there's also this:如果你没有吸气剂,还有这个:

listOfA.sort(Comparator.comparing(a -> a.field1));

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM