程序执行总是从C中的main开始吗？

Question

Must program execution start from main, or can the starting address be modified?

#include <stdio.h>

void fun();

#pragma startup fun

int main()
{
    printf("in main");
    return 0;
}

void fun()
{
    printf("in fun");
}

This program prints in fun before in main .

Answer 1

The '#pragma' command is specified in the ANSI standard to have an arbitrary implementation-defined effect. In the GNU C preprocessor, '#pragma' first attempts to run the game 'rogue'; if that fails, it tries to run the game 'hack'; if that fails, it tries to run GNU Emacs displaying the Tower of Hanoi; if that fails, it reports a fatal error. In any case, preprocessing does not continue.

-- Richard M. Stallman, The GNU C Preprocessor, version 1.34

Program execution starts at the startup code, or "runtime". This is usually some assembler routine called _start or somesuch, located (on Unix machines) in a file crt0.o that comes with the compiler package. It does the setup required to run a C executable (like, setting up stdin , stdout and stderr , the vectors used by atexit() ... for C++ it also includes initializing of global objects, ie running their constructors). Only then does control jump to main() .

As the quote at the beginning of my answer expresses so eloquently, what #pragma does is completely up to your compiler. Check its documentation. (I'd guess your pragma startup - which should be prepended with a # by the way - tells the runtime to call fun() first...)

Answer 2

As far as the ISO C Standard is concerned, the entry point for a C program is always main (unless some implementation-defined feature is used to override it) for a hosted implementation . For a "freestanding implementation" (typically an embedded system, often with no operating system), the entry point is implementation-defined.

Answer 3

C programs are not necessarily start from main() function. Some codes are executed before main() that zero out all uninitialized global variables and initialize other global variables with proper value. For example, consider the following code:

int a;
int b = 10;

int main()
{
    int c = a * b;
    return 0;
}

In the example code above, a and b are assigned 0 and 10 respectively before the execution of first line in main() .

The #pragma directive is there to define implementation-defined behaviour. Your code with #pragma may compile in some compiler but may not compile in another.