[英]How to use regular expression to extract *string* from an expression string?
I have an expression string as below (whole line as a string): 我有一个表达式字符串如下(整行作为一个字符串):
String s = prefix + "abc\"abc\"abc".toUpperCase();
I want to extract "abc\\"abc\\"abc" using a regular expression which understands "double quotes after a backslash is not the end of the string." 我想使用一个正则表达式提取“ abc \\” abc \\“ abc” ,该正则表达式理解“反斜杠后的双引号不是字符串的结尾。” How can I make it?
我该怎么做? Thank you very much!
非常感谢你!
FINALLY 最后
You guys gave me some hints and finally I figured it out and, this is my Java code: 你们给了我一些提示,最后我弄清楚了,这是我的Java代码:
public class RegExpTest {
private static final Pattern PATTERN = Pattern.compile("(([^\\\\]|^)\").*?([^\\\\]\")");
public static void main(String[] args) {
printStrings("He said \"Hello, \\\"\\\"\\\"\\\"name\\\"\", \"baby\"");
printStrings("\"Go away and \\\"never\\\" come back!\" he said.");
printStrings("\\\" outer \"inner\"");
}
private static void printStrings(String string) {
System.out.println(string);
System.out.println(extractStrings(string));
System.out.println();
}
private static List<String> extractStrings(String string) {
Matcher matcher = PATTERN.matcher(string);
List<String> resultList = new ArrayList<String>();
while (matcher.find()) {
String group = matcher.group();
if (!group.startsWith("\"")) {
group = group.substring(1); // remove first non-double-quoter
}
resultList.add(group);
}
return resultList;
}
}
It outputs as follows: 输出如下:
He said "Hello, \"\"\"\"name\"", "baby"
["Hello, \"\"\"\"name\"", "baby"]
"Go away and \"never\" come back!" he said.
["Go away and \"never\" come back!"]
\" outer "inner"
["inner"]
Thanks everyone. 感谢大家。
You could use: 您可以使用:
/".*?[^\]"/
All characters after the first "
until the next "
is reached which isn't preceded by a \\
. 到达第一个
"
直到下一个"
之后的所有字符,并且前面没有\\
。
Note that this also will not match ""
. 请注意,这也将与
""
不匹配。 Since there must be at least one character between the quotes for it to match. 由于引号之间必须至少有一个字符才能匹配。
"((?:\\"|[^"])+)"
首先匹配\\“,然后匹配任何非引号的字符串。group(1)是内部字符串。
I tried @PaulPRO's answer in Rad Software's Expression designer but it didn't work on your string for me. 我在Rad Software的Expression Designer中尝试了@PaulPRO的答案,但对我而言,它不适用于您的字符串。 This worked on your input using the tool I mentioned above.
使用上面提到的工具,这可以解决您的输入问题。
\".+?(\\|\"){1}
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