将数组排序到字典中

Question

I have and array of many strings. I wan't to sort them into a dictionary, so all strings starting the same letter go into one array and then the array becomes the value for a key; the key would be the letter with which all the words in it's value's array begin.

Example

Key = "A" >> Value = "array = apple, animal, alphabet, abc ..."
Key = "B" >> Value = "array = bat, ball, banana ..."

How can I do that? Thanks a lot in advance!

Answer 1

NSArray *list = [NSArray arrayWithObjects:@"apple, animal, bat, ball", nil];
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
for (NSString *word in list) {
    NSString *firstLetter = [[word substringToIndex:1] uppercaseString];
    NSMutableArray *letterList = [dict objectForKey:firstLetter];
    if (!letterList) {
        letterList = [NSMutableArray array];
        [dict setObject:letterList forKey:firstLetter];
    }
    [letterList addObject:word];
}
NSLog(@"%@", dict);

Answer 2

You can achieve what you want through the following steps:

1. Create an empty but mutable dictionary.
2. Get the first character.
3. If a key for that character does not exist, create it.
4. Add the word to the value of the key (should be an NSMutableArray).
5. Repeat step #2 for all keys.

Here is the Objective-C code for these steps. Note that I am assuming that you want the keys to be case insensitive .

// create our dummy dataset
NSArray * wordArray = [NSArray arrayWithObjects:@"Apple", 
                       @"Pickle", @"Monkey", @"Taco", 
                       @"arsenal", @"punch", @"twitch", 
                       @"mushy", nil];
// setup a dictionary
NSMutableDictionary * wordDictionary = [[NSMutableDictionary alloc] init];
for (NSString * word in wordArray) {
    // remove uppercaseString if you wish to keys case sensitive.
    NSString * letter = [[word substringWithRange:NSMakeRange(0, 1)] uppercaseString];
    NSMutableArray * array = [wordDictionary objectForKey:letter];
    if (!array) {
        // the key doesn't exist, so we will create it.
        [wordDictionary setObject:(array = [NSMutableArray array]) forKey:letter];
    }
    [array addObject:word];
}
NSLog(@"Word dictionary: %@", wordDictionary);

Answer 3

看一下这个主题，它们解决了几乎和你一样的问题 - 在目标中将NSArray过滤成新的NSArray-c让我知道它是否有用，所以我会再为你编写一个代码示例。

Answer 4

Use this to sort the contents of array in alphabetical order, further you design to the requirement

[keywordListArr sortUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

Answer 5

I just wrote this sample. It looks simple and does what you need.

NSArray *names = [NSArray arrayWithObjects:@"Anna", @"Antony", @"Jack", @"John", @"Nikita", @"Mark", @"Matthew", nil];

NSString *alphabet = @"ABCDEFGHIJKLMNOPQRSTUWXYZ";
NSMutableDictionary *sortedNames = [NSMutableDictionary dictionary];

for(int characterIndex = 0; characterIndex < 25; characterIndex++) {
    NSString *alphabetCharacter = [alphabet substringWithRange:NSMakeRange(characterIndex, 1)];
    NSArray *filteredNames = [names filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"SELF BEGINSWITH[C] %@", alphabetCharacter]];        
    [sortedNames setObject:filteredNames forKey:alphabetCharacter];
}

//Just for testing purposes let's take a look into our sorted data
for(NSString *key in sortedNames) {
    for(NSString *value in [sortedNames valueForKey:key]) {
        NSLog(@"%@:%@", key, value);
    }
}