如何在 python 中绘制有序树？

Question

I have an XML file whose underlying structure is an ordered tree. I use digraph in networks representing this tree and then I want to draw this tree. Suppose the digraph is G, then I write the following code:

map = dict(zip(id,tag)) # map from id to label
pos = nx.pydot_layout(G,prog = 'dot')
labels = nx.draw_networkx_labels(G, pos, map) 
nx.draw_networkx(G, pos, False, node_size = 1000, node_color = color)
plt.show()

but i cannot get a ordered tree. the order of silbing nodes are not in their original order.

I want to know how can I plot an ordered tree in python, thanks,

Answer 1

Don't call a variable map , there is a builtin called map .

You can use an OrderedDict to keep the items in order:

from collections import OrderedDict
from itertools import izip
themap = OrderedDict(izip(id,tag)) # map from id to label

You can also get it from PyPI if you have an older version of Python than 2.7 / 3.2.