[英]jQuery - Show only one div at any time
I'm working on a new menu, where I have a multiple hidden divs, but I only want to show one div on the page at any one time.我正在开发一个新菜单,其中有多个隐藏的 div,但我只想在任何时候在页面上显示一个 div。
Here is my code;这是我的代码; http://jsfiddle.net/sXqnD/
http://jsfiddle.net/sXqnD/
HTML is nice and simple; HTML 又好又简单;
<div id="linkwrapper">
<a id="link1" href="#">link1</a><br/>
<a id="link2" href="#">link2</a><br/>
<a id="link3" href="#">link3</a>
</div>
<div id="infocontent">
<div id="link1content">Information about 1.</div>
<div id="link2content">Information about 2.</div>
<div id="link3content">Information about 3.</div>
</div>
Here is my attempt at jQuery, which doesn't seem to play nicely.这是我对 jQuery 的尝试,它似乎玩得不太好。
$(document).ready(function(){
$('#infocontent').children().hide();
$('#linkwrapper a').click(function(){
var chosen1 = this.id;
$('#infocontent').children('div').each(function(i) {
var i = i+1;
if( $("#" + this.id).is(":visible") == true ) {
$("#" + this.id).hide(function(){
$("#" + chosen1 + "content").show();
});
return false;
} else {
$("#" + this.id).show();
return false;
}
});
});
});
Can anyone see where I have gone wrong or suggest a more elegant solution?谁能看到我哪里出错或提出更优雅的解决方案?
$('div').filter('#idOfDivToShow').show();
$('div').not('#idOfDivToShow').hide();
$('div')
will find all divs on your web page. $('div')
将在您的 web 页面上找到所有 div。 .filter
will search within the results that match $('div')
and match elements that have id=idOfDivToShow. .filter
将在匹配$('div')
的结果中搜索并匹配具有 id=idOfDivToShow 的元素。 .not
will search within the results that match $('div')
and match elements that don't have id=idOfDivToShow. .not
将在匹配$('div')
的结果中搜索并匹配没有 id=idOfDivToShow 的元素。
Finally, if you want to search only within a particular element, say #infocontent, then you could write:最后,如果您只想在特定元素中搜索,比如#infocontent,那么您可以编写:
$('#infocontent').filter('div').filter('#idOfDivToShow').show();
$('#infocontent').filter('div').not('#idOfDivToShow').hide();
I would suggest simplifying it in the click function to simply hide everything and then show the one you do want我建议在单击 function 中简化它,以简单地隐藏所有内容,然后显示您想要的内容
$('#linkwrapper a').click(function(){
$('#infocontent').children('div').each(function(i) { this.hide(); });
$('#' + this.id + 'content').show();
});
$(window).ready(function(){
/* hide the content divs */
$('#infocontent div').css('display', 'none');
/* add click events */
$('#linkwrapper a').click(function(){
$('#infocontent div').css('display', 'none');
$('#'+this.id+'content').css('display', 'block');
});
});
I would also take a moment to change your link href attributes to "javascript:void(null);"我还要花点时间将您的链接 href 属性更改为“javascript:void(null);” to prevent page jumping if the links are below the "fold" of the page.
如果链接位于页面的“折叠”下方,以防止页面跳转。
How about this?这个怎么样? http://jsfiddle.net/sXqnD/2/
http://jsfiddle.net/sXqnD/2/
<div id="linkwrapper">
<a id="link1" href="#">link1</a><br/>
<a id="link2" href="#">link2</a><br/>
<a id="link3" href="#">link3</a>
</div>
<div id="infocontent">
<div class="content" id="link1content">Information about 1.</div>
<div class="content" id="link2content">Information about 2.</div>
<div class="content" id="link3content">Information about 3.</div>
</div>
JS: JS:
$(document).ready(function(){
$('#infocontent').children().hide();
$('#linkwrapper a').click(function(){
var chosen1 = this.id;
$('.content').hide();
$('#' + chosen1 + 'content').show();
});
});
I think you'll find manipulating stuff by similarly-formatted IDs will not be very nice to work with in the long run though.我认为您会发现,从长远来看,通过类似格式的 ID 操作东西并不是很好。
For the quickest change:为了最快的改变:
From从
$(document).ready(function(){
$('#infocontent').children().hide();
$('#linkwrapper a').click(function(){
var chosen1 = this.id;
$('#infocontent').children('div').each(function(i) {
var i = i+1;
if( $("#" + this.id).is(":visible") == true ) {
$("#" + this.id).hide(function(){
$("#" + chosen1 + "content").show();
});
return false;
} else {
$("#" + this.id).show();
return false;
}
});
});
});
To至
$(document).ready(function () {
$('#infocontent').children().hide();
$('#linkwrapper a').click(function () {
var chosen1 = this.id;
$('#infocontent').children().hide();
$("#" + chosen1 + "content").show();
});
});
I basically replaced the.each() function with 1) hiding all the children, and then 2) showing the desired div我基本上替换了.each() function 1)隐藏所有孩子,然后 2)显示所需的 div
My solution is here: http://jsfiddle.net/sXqnD/8/我的解决方案在这里: http://jsfiddle.net/sXqnD/8/
Code:代码:
$(document).ready(function(){
var $allContentDivs = $('#infocontent div').hide(); // Hide All Content Divs
$('#linkwrapper a').click(function(){
var $contentDiv = $("#" + this.id + "content");
if($contentDiv.is(":visible")) {
$contentDiv.hide(); // Hide Div
} else {
$allContentDivs.hide(); // Hide All Divs
$contentDiv.show(); // Show Div
}
return false;
});
});
This is an answer which is close to what you had.这是一个接近你所拥有的答案。 It is based on this thought: - find the div's and only show the specified div if it's hidden - hide all other div's
它基于这个想法: - 找到 div 并仅在指定的 div 隐藏时显示它 - 隐藏所有其他 div
$(document).ready(function () {
$('#infocontent').children().hide();
$('#linkwrapper a').click(function () {
var chosen1 = this.id;
var divIdToShow = chosen1 + 'content';
$('#infocontent').children('div').each(function (i) {
var currentDiv = $(this);
if (this.id == divIdToShow) {
if (currentDiv.not(':visible')) {
currentDiv.show();
}
} else {
currentDiv.hide();
}
});
});
});
Thanks for all the advice.感谢所有的建议。
I found this to be the best solution for what I was trying to achieve.我发现这是我想要实现的最佳解决方案。
http://jsfiddle.net/sXqnD/15/ http://jsfiddle.net/sXqnD/15/
HTML HTML
<div id="linkwrapper">
<a id="link1" href="#">link1</a><br/>
<a id="link2" href="#">link2</a><br/>
<a id="link3" href="#">link3</a>
</div>
<div id="infocontent">
<div id="link1content">Information about 1.</div>
<div id="link2content">Information about 2.</div>
<div id="link3content">Information about 3.</div>
</div>
jQuery jQuery
$("#infocontent").hide();
$("#infocontent div").hide();
$('#linkwrapper a[id]').click(function(){
var vsubmen = this.id +"content";
if( $("#infocontent").is(":visible") == false ) {
$("#" + vsubmen).show('fast',function() {
$("#infocontent").slideDown();
});
} else if ( $("#" + vsubmen).is(":visible") == false ) {
$("#infocontent").slideUp('slow',function(){
$("#infocontent div").hide();
$("#" + vsubmen).show();
$("#infocontent").slideDown('slow');
});
} else {
$("#infocontent").slideUp('slow',function(){
$("#infocontent div").hide();
});
}
return false;
});
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