这个简单的 bash 命令有什么问题？
[英]what's wrong with this simple bash command?
问题描述
$i is not working... it's making me crazy! 
$i 不工作......这让我发疯了！
for i in {1..200};
do echo "/scratch/inputTest/prob/timit.test.pg.list_10_$i_prob.bin" >> longProbList;
done
in the file there is just在文件中只有
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
2 个解决方案
解决方案1
7 已采纳 2011-08-13 01:31:04
It thinks your variable name is $i_prob since an underscore is a valid character for a variable name.它认为您的变量名是$i_prob因为下划线是变量名的有效字符。 Use ${i} to fix this:使用${i}来解决这个问题：
for i in {1..200};
do echo "/scratch/inputTest/prob/timit.test.pg.list_10_${i}_prob.bin" >> longProbList;
done
解决方案2
1 2011-08-13 01:33:47
You've forgotten the " " around $i你忘记了 $i 周围的 " "
for i in {1..200};
do echo "/scratch/inputTest/prob/timit.test.pg.list_10_"$i"_prob.bin" >> longProbList;
done
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