[英]Copying an XML document into a String Variable in Java
I am trying to copy an entire XML document, tagnames/tagtypes irrelavant, into a String varible.我正在尝试将整个 XML 文档(标记名/标记类型无关)复制到字符串变量中。 Language to be used is Java.使用的语言是 Java。 I used ReadAllText to do it in C#, but I need to find an equivalent of that command in Java or another idea to be able to have the entire XML document as a String.我使用 ReadAllText 在 C# 中执行此操作,但我需要在 Java 中找到与该命令等效的命令,或者其他能够将整个 XML 文档作为字符串的想法I have been working on this for a while now.我已经为此工作了一段时间。 This is part of a bigger project.这是一个更大项目的一部分。 This is the only thing that is left to be done.这是唯一需要做的事情。 Any suggestions?有什么建议么? Thanks in Advance.提前致谢。
Well since this is java and not a scripting language, you will just need to use a scanner or file reader and read it line by line and append it into a single string.好吧,因为这是 java 而不是脚本语言,所以您只需要使用扫描仪或文件阅读器并逐行读取,然后将 append 转换为单个字符串。
This website has a great overview of file io in java.该网站对 java 中的文件 io 有一个很好的概述。 I actually learned a lot even after knowing about file io.即使在了解文件 io 之后,我实际上也学到了很多东西。
Here is a sample of what you could do:这是您可以执行的操作的示例:
private void processFile(File file)
{
StringBuilder allText = new StringBuilder();
String line;
Scanner reader = null;
try {
FileInputStream fis = new FileInputStream(propertyFile);
InputStreamReader in = new InputStreamReader(fis, "ISO-8859-1");
reader = new Scanner(in);
while(reader.hasNextLine() && !errorState)
{
line = reader.nextLine();
allText.append(line);
}
} catch (FileNotFoundException e)
{
System.err.println("Unable to read file");
errorState=true;
} catch (UnsupportedEncodingException e) {
System.err.println("Encoding not supported");
errorState=true;
}
finally
{
reader.close();
}
}
Try following code:试试下面的代码:
public String convertXMLFileToString(String fileName)
{
try {
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
InputStream inputStream = new FileInputStream(new File(fileName));
org.w3c.dom.Document doc = documentBuilderFactory.newDocumentBuilder().parse(inputStream);
StringWriter stw = new StringWriter();
Transformer serializer = TransformerFactory.newInstance().newTransformer();
serializer.transform(new DOMSource(doc), new StreamResult(stw));
return stw.toString();
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
use an StringWriter
with a StreamResult
.将StringWriter
与StreamResult
一起使用。
note, be very careful what you do with that string after that .请注意,之后要非常小心地处理该字符串。 if you later write it to a stream/byte[] of some sort using the wrong character encoding, you will generate broken xml data.如果您稍后使用错误的字符编码将其写入某种流/字节[],您将生成损坏的 xml 数据。
I used a buffered Reader the last time I did this.我上次这样做时使用了缓冲阅读器。 Worked well.工作得很好。
String output = "";
try {
FileInputStream is = new FileInputStream(file);
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = "";
while ((line = br.readLine()) != null) {
output = output + line;
}
br.close();
is.close();
} catch(IOException ex) {
//LOG!
}
My original implementation was to use an actual buffer but I seemed to keep having issues with flushing the buffer so I went this way which is super easy.我最初的实现是使用一个实际的缓冲区,但我似乎一直在刷新缓冲区时遇到问题,所以我采用了这种方式,非常简单。
Many answers that get it almost, but not quite, correct.许多答案几乎但不完全正确。
If you positively know the source encoding, you can do this:如果你肯定知道源编码,你可以这样做:
String file2string(File f, Charset cs) throws IOException {
ByteArrayOutputStream out = new ByteArrayOutputStream(10000);
InputStream in = new BufferedInputStream(new FileInputStream(f));
int c;
while ((c = in.read()) != -1)
out.write(c);
in.close();
return out.toString(cs.name());
}
If you don't know the source encoding, rely on the XML parser to detect it and control the output:如果您不知道源编码,请依靠 XML 解析器来检测并控制 output:
String transform2String(File f, Charset cs) throws IOException,
TransformerFactoryConfigurationError, TransformerException {
Transformer t = TransformerFactory.newInstance().newTransformer();
t.setOutputProperty(OutputKeys.ENCODING, cs.name());
ByteArrayOutputStream out = new ByteArrayOutputStream(10000);
t.transform(new StreamSource(new BufferedInputStream(
new FileInputStream(f))), new StreamResult(out));
return out.toString(cs.name());
}
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