为什么QWidget的析构函数不是虚拟的？

Question

Looking at qwidget.h, I found the destructor as below:

~QWidget();

I was wondering why this is not declared as virtual

Answer 1

The destructor is virtual, because QWidget derives from QObject which does have a virtual destructor. Why it's not declared virtual in the code is a either style issue or a harmless mistake. I would have declared it virtual myself.