成功提交后获取表单弹出窗口
[英]Get form popup upon successful submission
问题描述
How do I go about getting this form to display "Submitted" using basic javascript popup window upon successful submission? 
成功提交后，如何使用基本的javascript弹出窗口将此表格显示为“已提交”？
<!DOCTYPE html>
<html>
<head>
<title>Site :: </title>
<link rel="stylesheet" media="screen" href="css/wicahost.css" />
<link rel="stylesheet" media="screen" href="css/global.css" />
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.js"></script>
<?php require_once('inc/php/clearfieldJs.php'); ?>
<script type="text/javascript">
$(document).ready(function() {
$("#splashtease").RSV({
rules: [
"required,emAdd,Please enter your email address.",
"valid_email,emAdd,Please enter a valid email address.",
]
});
});
</script>
</head>
<body>
<script src="http://www.benjaminkeen.com/software/rsv/jquery/jquery.rsv.js"></script>
<div id="splashTeaserBox">
<h1 class="wicasplashcenter">Signup!</h1>
<div class="wicasplashcenter">Captivating interests and inspiring collaboration.</div>
<form id="splashtease" action="inc/subscribe.php" method="post">
<?php $usrBrowser = $_SERVER['HTTP_USER_AGENT']; $todayDt = date('Y-m-d'); ?>
<input type="text" name="emAdd" class="splashtease" value="Your Email Address ..." onFocus="clearText(this)" />
<input type="hidden" name="brwsr" value="<?php echo $usrBrowser; ?>" style="margin:0; padding:0;" />
<input type="hidden" name="dt" value="<?php echo $todayDt; ?>" style="margin:0; padding:0;" />
<input type="submit" name="submit" value="" class="splashteasesub" />
</form>
</div><!--splashTeaserBox--></body>
</html>
PHP 的PHP
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="dnbame"; // Database name
$tbl_name="subscriber"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
/* Obliterate bad input */
$goodEmail = mysql_real_escape_string($_POST['emAdd']);
$goodBrowser = mysql_real_escape_string($_POST['brwsr']);
$goodDate = mysql_real_escape_string($_POST['dt']);
$sql= "INSERT INTO subscriber (Email, Browser, DateSubscribed) VALUES('$goodEmail','$goodBrowser','$goodDate')";
$result = mysql_query($sql);
if (!$result) {
die('Invalid Email, please retry.');
}
else{
echo var success;
}
?>
3 个解决方案
解决方案1
0 2011-08-18 23:10:35
A basic example: 一个基本的例子：
In subscribe.php, change: 在subscribe.php中，更改：
else{
echo var success;
}
to: 至：
else {
echo "<html><body onload=\"alert('Submitted');\"><p>Submission successful.</p></body></html>";
}
解决方案2
0 2011-08-18 23:34:26
@user886187's solution will reload the page upon submission and then display a JavaScript pop-up when the page has reloaded. @ user886187的解决方案将在提交后重新加载页面，然后在重新加载页面后显示JavaScript弹出窗口。
You might want to submit the form and then display the pop-up without reloading the page. 您可能要提交表单，然后显示弹出窗口而不重新加载页面。 In that case you need to submit the form via Ajax, and then alert "submitted" in the callback function: 在这种情况下，您需要通过Ajax提交表单，然后在回调函数中提醒“已提交”：
function callback() {
alert('submitted');
}
Here's a tutorial on how to submit a form via Ajax: 这是有关如何通过Ajax提交表单的教程：
http://net.tutsplus.com/tutorials/javascript-ajax/submit-a-form-without-page-refresh-using-jquery/ http://net.tutsplus.com/tutorials/javascript-ajax/submit-a-form-without-page-refresh-using-jquery/
解决方案3
0 2011-08-19 01:45:38
put this code in your subcribe.php 将此代码放在您的subcribe.php中
else {
header ('Location: formPage.php?message=Success');
}
and this code inside head of formPage.php 和这段代码在formPage.php的头里面
<head>
<?php if ($_GET['message']) {echo '<script type="text/javascript">alert("Form Submited Successfully");</script>';} ?>
</head>
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.