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Groovy如何处理闭包作用域和递归?

[英]How does Groovy handle closure scope and recursion?

I have a recursive Python function that builds a tree, and I'm trying to translate it into Groovy. 我有一个递归的Python函数,它可以构建树,并且正在尝试将其转换为Groovy。

Here's the Python version... 这是Python版本...

def get_tree(vertices):
    results = []

    if type(vertices) != list:
        vertices = [vertices]

    for vertex in vertices:
        results.append(vertex)
        children = get_children(vertex)
        if children:
            child_tree = get_tree(children)
            results.append(child_tree)

    return results

Here's the output of get_tree(1)... 这是get_tree(1)的输出...

  [1, [2, 3, 4, [5, 3]]]

And here's my attempt to translate this into a Groovy closure... 这是我尝试将其转换为Groovy闭包...

_tree = { vertices ->

  results = []

  vertices.each() {
    results << it
    children = it."$direction"().toList()
    if (children) {
      child_tree = _tree(children)
      results << child_tree
    }
  }
  results
}

But this doesn't work -- this is what it returns... 但这不起作用-这就是它的返回值...

gremlin> g.v(1).outTree()    
==>[v[5], v[3], (this Collection), (this Collection)]

What are those "this Collection"s about? 这些“收藏”是关于什么的?

I have only a cursory understanding of Groovy, and I suspect it's something to do with how Groovy handles recursion and closure scope. 我对Groovy只是一个粗略的了解,我怀疑这与Groovy如何处理递归和关闭范围有关。

Please enlighten me :) 请赐教我:)

The solution was to add def to results = [] : 解决方案是将def添加到results = []

_tree = { vertices ->

  def results = []

  vertices.each() {
    results << it
    children = it."$direction"().toList()
    if (children) {
      child_tree = _tree(children)
      results << child_tree
    }
  }
  results
}

See https://groups.google.com/d/msg/gremlin-users/iCPUifiU_wk/mrUhsjOM2h0J 请参阅https://groups.google.com/d/msg/gremlin-users/iCPUifiU_wk/mrUhsjOM2h0J

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