比较std :: wstring和std :: string

Question

How can I compare a wstring , such as L"Hello" , to a string ? If I need to have the same type, how can I convert them into the same type?

Answer 1

Since you asked, here's my standard conversion functions from string to wide string, implemented using C++ std::string and std::wstring classes.

First off, make sure to start your program with set_locale :

#include <clocale>

int main()
{
  std::setlocale(LC_CTYPE, "");  // before any string operations
}

Now for the functions. First off, getting a wide string from a narrow string:

#include <string>
#include <vector>
#include <cassert>
#include <cstdlib>
#include <cwchar>
#include <cerrno>

// Dummy overload
std::wstring get_wstring(const std::wstring & s)
{
  return s;
}

// Real worker
std::wstring get_wstring(const std::string & s)
{
  const char * cs = s.c_str();
  const size_t wn = std::mbsrtowcs(NULL, &cs, 0, NULL);

  if (wn == size_t(-1))
  {
    std::cout << "Error in mbsrtowcs(): " << errno << std::endl;
    return L"";
  }

  std::vector<wchar_t> buf(wn + 1);
  const size_t wn_again = std::mbsrtowcs(buf.data(), &cs, wn + 1, NULL);

  if (wn_again == size_t(-1))
  {
    std::cout << "Error in mbsrtowcs(): " << errno << std::endl;
    return L"";
  }

  assert(cs == NULL); // successful conversion

  return std::wstring(buf.data(), wn);
}

And going back, making a narrow string from a wide string. I call the narrow string "locale string", because it is in a platform-dependent encoding depending on the current locale:

// Dummy
std::string get_locale_string(const std::string & s)
{
  return s;
}

// Real worker
std::string get_locale_string(const std::wstring & s)
{
  const wchar_t * cs = s.c_str();
  const size_t wn = std::wcsrtombs(NULL, &cs, 0, NULL);

  if (wn == size_t(-1))
  {
    std::cout << "Error in wcsrtombs(): " << errno << std::endl;
    return "";
  }

  std::vector<char> buf(wn + 1);
  const size_t wn_again = std::wcsrtombs(buf.data(), &cs, wn + 1, NULL);

  if (wn_again == size_t(-1))
  {
    std::cout << "Error in wcsrtombs(): " << errno << std::endl;
    return "";
  }

  assert(cs == NULL); // successful conversion

  return std::string(buf.data(), wn);
}

Some notes:

• If you don't have std::vector::data() , you can say &buf[0] instead.
• I've found that the r -style conversion functions mbsrtowcs and wcsrtombs don't work properly on Windows. There, you can use the mbstowcs and wcstombs instead: mbstowcs(buf.data(), cs, wn + 1); , wcstombs(buf.data(), cs, wn + 1);

In response to your question, if you want to compare two strings, you can convert both of them to wide string and then compare those. If you are reading a file from disk which has a known encoding, you should use iconv() to convert the file from your known encoding to WCHAR and then compare with the wide string.

Beware, though, that complex Unicode text may have multiple different representations as code point sequences which you may want to consider equal. If that is a possibility, you need to use a higher-level Unicode processing library (such as ICU) and normalize your strings to some common, comparable form.

Answer 2

You should convert the char string to a wchar_t string using mbstowcs , and then compare the resulting strings. Notice that mbstowcs works on char * / wchar * , so you'll probably need to do something like this:

std::wstring StringToWstring(const std::string & source)
{
    std::wstring target(source.size()+1, L' ');
    std::size_t newLength=std::mbstowcs(&target[0], source.c_str(), target.size());
    target.resize(newLength);
    return target;
}

I'm not entirely sure that that usage of &target[0] is entirely standard-conforming, if someone has a good answer to that please tell me in the comments. Also, there's an implicit assumption that the converted string won't be longer (in number of wchar_t s) than the number of char s of the original string - a logical assumption that still I'm not sure it's covered by the standard.

On the other hand, it seems that there's no way to ask to mbstowcs the size of the needed buffer, so either you go this way, or go with (better done and better defined) code from Unicode libraries (be it Windows APIs or libraries like iconv).

Still, keep in mind that comparing Unicode strings without using special functions is slippery ground, two equivalent strings may be evaluated different when compared bitwise.

Long story short: this should work, and I think it's the maximum you can do with just the standard library, but it's a lot implementation-dependent in how Unicode is handled, and I wouldn't trust it a lot. In general, it's just better to stick with an encoding inside your application and avoid this kind of conversions unless absolutely necessary, and, if you are working with definite encodings, use APIs that are less implementation-dependent.

Answer 3

Think twice before doing this — you might not want to compare them in the first place. If you are sure you do and you are using Windows, then convert string to wstring with MultiByteToWideChar , then compare with CompareStringEx .

If you are not using Windows, then the analogous functions are mbstowcs and wcscmp . The standard wide character C++ functions are often not portable under Windows; for instance mbstowcs is deprecated.

The cross-platform way to work with Unicode is to use the ICU library.

Take care to use special functions for Unicode string comparison, don't do it manually. Two Unicode strings could have different characters, yet still be the same.

wstring ConvertToUnicode(const string & str)
{
    UINT  codePage = CP_ACP;
    DWORD flags    = 0;
    int resultSize = MultiByteToWideChar
        ( codePage     // CodePage
        , flags        // dwFlags
        , str.c_str()  // lpMultiByteStr
        , str.length() // cbMultiByte
        , NULL         // lpWideCharStr
        , 0            // cchWideChar
        );
    vector<wchar_t> result(resultSize + 1);
    MultiByteToWideChar
        ( codePage     // CodePage
        , flags        // dwFlags
        , str.c_str()  // lpMultiByteStr
        , str.length() // cbMultiByte
        , &result[0]   // lpWideCharStr
        , resultSize   // cchWideChar
        );
    return &result[0];
}