[英]Django class based views
url pattern 网址格式
url(r'(?P<username>\w+)/$', ProfileView.as_view()),
view 视图
class ProfileView(TemplateView):
template_name = "home.html"
@method_decorator(login_required(login_url='/'))
def dispatch(self, *args, **kwargs):
return super(ProfileView, self).dispatch(*args, **kwargs)
My main view function makes sure logged in users are redirected to their profile page, thus: 我的主视图功能确保已登录的用户被重定向到其个人资料页面,因此:
WEBSITE/users/someuser
Will call to my ProfileView.as_view(), However this still permits users to alter the url to something like: 将调用我的ProfileView.as_view(),但是,这仍然允许用户将url更改为:
WEBSITE/users/someotheruser
Which isn't harmfull because it will still just render the request.user data, but I would rather catch this behaviour by always redirecting to the current user.. I don't really understand how? 这不是有害的,因为它仍然只会呈现request.user数据,但是我宁愿通过始终重定向到当前用户来捕获此行为。
Try this: 尝试这个:
class ProfileView(TemplateView):
template_name = "home.html"
@method_decorator(login_required(login_url='/'))
def dispatch(self, *args, **kwargs):
if request.user.username == username:
return super(ProfileView, self).dispatch(*args, **kwargs)
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