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MySQL和PHP:联接和计数

[英]MySQL & PHP: Joins & Counts

I want to select all users from my table where access_level_id!=0. 我想从我的表中选择所有用户,其中access_level_id!= 0。 I also want to count the number of entries in another table where the user id matches a field (this could be 0 or 100). 我还想统计用户ID与字段匹配的另一个表中的条目数(可以为0或100)。

I have: 我有:

SELECT users.id, count(clients.id) as count FROM $db[users] as users 
                              LEFT JOIN $db[clients] as clients ON users.id=clients.salesrep_id
                              WHERE users.access_level_id!='0'

This is returning just a single number (17) 这仅返回一个数字(17)

You have to group the results. 您必须将结果分组。 Try adding GROUP BY users.id to your Query. 尝试将GROUP BY users.id添加到查询中。

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