[英]Problems with fetching data from a database
My Current Code: 我当前的代码:
<?php
if(require("connect.php"))
{
$result = $mysqli->query('SELECT title, description, portfolio FROM Portfolio;');
while($o = $result->fetch_object())
{
$title=htmlspecialchars($o->title);
$description=htmlspecialchars($o->description);
$portfolio=htmlspecialchars($o->portfolio);
echo <<<ARTBOX
<div class="artbox">
<div class="photocontainer">
<img src="$portfolio" alt="$title" />
</div>
<div class="artboxtitle">
$title
</div>
<div class="artboxdescription">
$description
</div>
<div class="artboxenquiry">
<img src="images/enquiry.png" alt="Make an Enquiry" href="#" />
</div>
</div>
ARTBOX;
}
}
else
{
echo "An error occurred, please try again.";
}
?>
Returns the error: "Fatal error: Call to a member function fetch_object() on a non-object in ..." 返回错误:“致命错误:在...中的非对象上调用成员函数fetch_object()”
Can someone tell me where I am going wrong? 有人可以告诉我我要去哪里了吗?
Have a look at the return value of mysqli::query() . 看一下mysqli :: query()的返回值。 It can return
FALSE
in case of an error. 如果发生错误,它可以返回
FALSE
。 So $result
will be FALSE
and FALSE->fetch_object()
doesn't make sense - and it does call a member function on a non-object. 因此
$result
将为FALSE
而FALSE->fetch_object()
则没有意义-并且它确实在非对象上调用了成员函数。
For debugging, you can output error messages: 为了进行调试,您可以输出错误消息:
$result = $mysqli->query('SELECT title, description, portfolio FROM Portfolio;');
if (!$result) {
die($mysqli->error);
}
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