访问数组的最后一个元素

Question

I'm trying to access the last element in an array in C++ (more specifically, I'm trying to convert an integer into a character array and then access the last digit). Here's what I've come up with so far:

int number_to_convert = 1234;
char * num_string;
sprintf(num_string, "%d", number_to_convert);
printf("Number: %d Sizeof num_string: %d Sizeof *num_string: %d Sizeof num_string[0]: %d\n", number_to_convert, sizeof(num_string), sizeof(*num_string), sizeof(num_string[0]));

Using this info I tried several different combinations to access the last element:

num_string[sizeof(number_to_convert)/sizeof(*number_to_convert)-1];
num_string[sizeof(number_to_convert)-sizeof(char)]

Maybe there's a better way to get the last digit, but this is the best way I could find. I want the last character (not the null character).

Answer 1

For the last decimal digit of n , try n % 10 .

To get the textual numeral character for that digit, use '0' + (n % 10) .

For any other number base, replace 10 with that base.

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The "because I can" way:

std::ostringstream s;
s << n;
char last_digit = *s.str().rbegin();

Or even:

const char last_digit = *static_cast<std::ostringstream&>(std::ostringstream() << n).str().rbegin();