如何通过php从mysql获取如下数组？

Question

I have a table like this-

event (id,name,date)

I need a result set like this

$result = array(
    '1'=>array(
        array('id'=>2,'name'=>'foolball match','date'=>'2011-01-23'),
        array('id'=>5,'name'=>'cricket match','date'=>'2011-01-27')
    ),
    '3'=>array(
        array('id'=>11,'name'=>'100 m run','date'=>'2011-03-12'),
        array('id'=>27,'name'=>'Basket Ball','date'=>'2011-03-20'),
        array('id'=>43,'name'=>'foolball match','date'=>'2011-03-29')
    )
);

Here array keys (1,3) represents months (jan,mar). Events will be stored under these month number key. Here 2 is missing because there are no events in februry.

Can anybody please help me?

Answer 1

Try this

$result = array();
$year = 2011;
$query = 'SELECT `id`, `name`, `date`, EXTRACT(MONTH FROM `date`) AS `month` FROM `event` WHERE EXTRACT(YEAR FROM `date`) = "' . $year . '" ORDER BY `date` DESC';
$res = mysql_query($query);
while ($row = mysql_fetch_assoc($res)) {
  $result[$row['month']][] = $row;
}

Answer 2

提取数据后，循环遍历PHP中的结果集，处理日期值。

Answer 3

//assuming events are in this format
$events = array(
    array('id'=>2,'name'=>'foolball match','date'=>'2011-01-23'),
    array('id'=>5,'name'=>'cricket match','date'=>'2011-01-27'),
    array('id'=>11,'name'=>'100 m run','date'=>'2011-03-12'),
    array('id'=>27,'name'=>'Basket Ball','date'=>'2011-03-20'),
    array('id'=>43,'name'=>'foolball match','date'=>'2011-03-29')
);

$result = array();
foreach ($events as $event) {
    $month = (int)date('m', strtotime($event['date']));
    $result[$month][] = $event;
}
var_dump($result);