[英]C puzzle…How Can I pass variadic arguments into a macro?
I got stuck here... 我被困在这里......
#include <stdio.h>
#define DBG_LVL(lvl, stmt) \
do{ \
if(lvl>1) printf stmt; \
}while(0)
#define DBG_INFO(stmt) DBG_LVL(1, stmt)
#define DBG_ERROR(stmt) DBG_LVL(2, stmt)
int main()
{
DBG_INFO(("hello, %s!\n", "world"));
DBG_ERROR(("crazy, %s!\n", "world"));
return 0;
}
As you can see, the code above uses macros like "DBG_INFO" or "DBG_ERROR" to control debug information level. 如您所见,上面的代码使用“DBG_INFO”或“DBG_ERROR”等宏来控制调试信息级别。
Now for some reason, I have to replace DBG_LVL()
with a new function. 现在由于某种原因,我必须用新函数替换
DBG_LVL()
。
void myprint(int lvl, const char * format, ...);
The only difference is the debug level is taken as its fisrt parameter. 唯一的区别是调试级别被视为其fisrt参数。 I was thinking:
我刚在想:
#define DBG_LVL(lvl, stmt) myprint(lvl, stmt)
Of course it failed, because the "stmt" expression includes parentheses around .
当然它失败了,因为“stmt”表达式包括括号 。 Then I googled around trying to find a way to strip the parentheses, seems there's nothing could help.
然后我用Google搜索试图找到剥离括号的方法,似乎没有什么可以帮助。 I also tried some tricks to pass parameters into "stmt", still failed... :(
我也尝试了一些技巧将参数传递给“stmt”,仍然失败...... :(
Can you help me? 你能帮助我吗?
# define EXPAND_ARGS(...) __VA_ARGS__
# define DBG_LVL(lvl, stmt) myprint(lvl, EXPAND_ARGS stmt);
Don't write this as a macro. 不要把它写成宏。
Write instead an ordinary varargs function: 写一个普通的varargs函数:
void DBG_LVL(int level, char *fmt, ...)
{
if (level < 1) return;
va_list args;
va_start(args, fmt);
vaprintf(fmt, args);
va_end(args);
}
For myprint()
, define a similar vamyprint(int lvl, const char *format, va_list ap)
as well, and forward the same way. 对于
myprint()
, myprint()
定义类似的vamyprint(int lvl, const char *format, va_list ap)
,并以相同的方式转发。
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