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使用LIKE对数组进行Postgres查询

[英]Postgres Query of an Array using LIKE

I am querying a database in Postgres using psql. 我正在使用psql查询Postgres中的数据库。 I have used the following query to search a field called tags that has an array of text as it's data type: 我使用以下查询来搜索名为tags的字段,该字段具有文本数组作为其数据类型:

select count(*) from planet_osm_ways where 'highway' = ANY(tags);

I now need to create a query that searches the tags fields for any word starting with the letter 'A'. 我现在需要创建一个查询,在标签字段中搜索以字母“A”开头的任何单词。 I tried the following: 我尝试了以下方法:

select count(*) from planet_osm_ways where 'A%' LIKE ANY(tags);

This gives me a syntax error. 这给了我一个语法错误。 Any suggestions on how to use LIKE with an array of text? 有关如何使用LIKE与文本数组的任何建议?

Use the unnest() function to convert array to set of rows: 使用unnest()函数将数组转换为行集:

SELECT count(distinct id)
FROM (
    SELECT id, unnest(tags) tag
    FROM planet_osm_ways) x
WHERE tag LIKE 'A%'

The count(dictinct id) should count unique entries from planet_osm_ways table, just replace id with your primary key's name. count(dictinct id)应该计算planet_osm_ways表中的唯一条目,只需用您的主键名称替换id

That being said, you should really think about storing tags in a separate table, with many-to-one relationship with planet_osm_ways , or create a separate table for tags that will have many-to-many relationship with planet_osm_ways . 话虽这么说,你应该考虑将标签存储在一个单独的表中,与planet_osm_waysplanet_osm_ways关系,或者为与planet_osm_ways多对多关系的标签创建一个单独的表。 The way you store tags now makes it impossible to use indexes while searching for tags, which means that each search performs a full table scan. 现在存储标签的方式使得在搜索标签时无法使用索引,这意味着每次搜索都会执行全表扫描。

Here is another way to do it within the WHERE clause: 这是在WHERE子句中执行此操作的另一种方法:

SELECT COUNT(*)
FROM planet_osm_ways 
WHERE (
  0 < (
    SELECT COUNT(*) 
    FROM unnest(planet_osm_ways) AS planet_osm_way
    WHERE planet_osm_way LIKE 'A%'
  )
);

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