[英]Producing a subList from a vector<int> in C++
is there a built-in STL method to do that? 是否有内置的STL方法来做到这一点?
In java, there is list.subList(a,b) for extracting [a,b). 在java中,有list.subList(a,b)用于提取[a,b)。 Similar method in STL C++? STL C ++中的类似方法?
当然。
std::vector<int> subList(&originalVector[a], &originalVector[b]);
You can do: 你可以做:
#include <vector>
#include <cassert>
int main() {
std::vector<int> x;
for (int i=0; i<10; ++i) {
x.push_back(i);
}
// Here we create a copy of a subsequence/sublist of x:
std::vector<int> slice_of_x(x.begin() + 3, x.begin() + 7);
assert(slice_of_x.size() == 7-3);
assert(slice_of_x[0] == 3);
return 0;
}
This will make a copy of the requested part of x
. 这将复制x
的请求部分。 If you don't need a copy and would like to be more efficient, it might be preferable to pass around iterator (or pointer) pairs. 如果您不需要副本并希望提高效率,则最好传递迭代器(或指针)对。 That would avoid copying. 这样可以避免复制。
当然。
std::vector<int> subList(originalVector.begin() + a, originalVector.begin() + b);
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