如何使用 javascript 检测 firefox 手机

Question

I'm using the following code to detect whether the browser being used on my mobile site matches a certain crieteria:

var isiPhone = navigator.userAgent.match(/iPhone/i) != null;
if (isiPhone){ alert ('iphone');

but if I attempt to do this for Firefox / Mozilla, I can't get it to work. I've tried:

var isFirefox = navigator.userAgent.match(/Mozilla/i != null);

and

var isFirefox = navigator.userAgent.match(/Firefox/i != null);

I visited whatismyuseragent.com and got the following:

Mozilla/5.0 (Android;Linux armv7l; rv6.0) Gecko/20110811 Gecko Firefox/6.0 Fennec/6.0

Any idea how I properly detect this? I need to write some firefox specific code.

Answer 1

You can use the navigator.userAgent to detect the browser and navigator.platform to detect the current platform.

To Detect Firefox:

var is_firefox = navigator.userAgent.toLowerCase().indexOf('firefox') > -1;

To Detect Android:

var is_android = navigator.platform.toLowerCase().indexOf("android") > -1;

To Detect Both:

if(is_firefox && is_android)
    //Do Work

I would recommend using something like modernizr to avoid browser detection and focus on feature detection.

Answer 2

Firefox的移动版本是Fennec，因此只需搜索以下内容：

var is_Firefox = navigator.userAgent.toLowerCase().indexOf('fennec') > -1;

Answer 3

var isFirefox = /Android.+Firefox\\//.test(navigator.userAgent);

Answer 4

you can check from user agent if it's contain firefox or android, for this maybe you need some code with regex

Answer 5

None of the above functions were working for me, specifically buriwoy was detecting either android or firefox, this version of his function works:

function detectAndroidFirefox () {
   var agent = navigator.userAgent.toLowerCase();
   if(agent.indexOf('firefox') >= 0){
     if(agent.indexOf("android") >= 0){
       return true;    
     } else{
       return false;
     }
   } else{
     return false;
   }
}

Answer 6

Rion's answer doesn't work (at least anymore), because navigator.platform doesn't return Android, it returns Linux.

I wrote a function which seems to work:

function detectAndroidFirefox () {
   var agent = navigator.userAgent.toLowerCase();
   return (agent.indexOf('firefox') + agent.indexOf("android")) >= 0;
}

Thought maybe someone will need this.