如何拖动DIV，使其宽度和高度为负值？

Question

I'm a bit stumped here. I am developing a feedback utility that will allow the user to "draw" boxes on a web page to highlight problem areas. Right now I have an overlay DIV that fills the screen and jQuery allows you to draw red outlined DIVs by clicking and dragging.

Here is the JS:

{
    var $feedbackOverlay = jQuery('#feedbackOverlay');
    var $original = { top: 0, left:0 };
    $feedbackOverlay.bind('mousedown', function (e)
    {
        jQuery('<div id="currentHighlight"></div>')
            .css('width', '1px')
            .css('height', '1px')
            .css('border', 'solid 3px #ff0000')
            .css('border-radius', '5px')
            .css('position', 'absolute')
            .css('left', e.pageX)
            .css('top', e.pageY)
            .css('z-index', '8000001')
            .appendTo('body');

        $original = { top: e.pageY, left: e.pageX };
    });
    $feedbackOverlay.bind('mousemove', function (e)
    {
        var $currentHighlight = jQuery('#currentHighlight');
        if ($currentHighlight.length > 0)
        {
            var $pos = { top: e.pageY, left: e.pageX };

            if($pos.top < $original.top) $currentHighlight.css('top', $pos.top);
            if ($pos.left < $original.left) $currentHighlight.css('left', $pos.left);

            $currentHighlight.height(Math.abs($pos.top - $original.top));
            $currentHighlight.width(Math.abs($pos.left - $original.left));
        }
    });
    $feedbackOverlay.bind('mouseup', function (e)
    {
        var $currentHighlight = jQuery('#currentHighlight');
        $currentHighlight.removeAttr('id');
    });
    var $feedbackInstructions = jQuery('#feedbackInstructions');
    $feedbackInstructions.fadeIn(1000, function ()
    {
        setTimeout(function ()
        {
            $feedbackInstructions.fadeOut(1000);
        }, 3000);
    });

    $feedbackOverlay.height(jQuery(document).height());
});

Here is a jsFiddle for the above:

http://jsfiddle.net/Chevex/RSYTq/

The problem is that I can't drag the boxes up or left. The first click puts the top left corner where the mouse clicked. After that subsequent dragging will change the width of the box. Letting go of the mouse completes the box and you may then start drawing another one. If you try to drag the DIV left or up while drawing it's width will remain at 0 but won't go negative.

Answer 1

在这里您可以找到有效的解决方案： http : //jsfiddle.net/RSYTq/34/

Answer 2

There's no such thing aa negative width - these are not coorindinates. You need to reposition and recalculate the corner positions relative to the corner that's not being moved.

Answer 3

Something like this will get you closer to what you want: http://jsfiddle.net/RSYTq/18/

Doesn't quite handle move up and to the left and then switching to moving down and to the right quite right yet but it gives you the idea.

Answer 4

听起来您需要检查单击源（x，y）是否大于当前鼠标位置，然后交换左上角用于CSS的那个。

Answer 5

You would need to track the original start point somewhere (variables, data attributes on #currentHighlight , wherever you want), and check for width or height < 0. When so, set the #currentHighlight left / top CSS to be offset by original + (e.pageX - $currentHighlight.position().left) (for example). Then set the #currentHighlight width/height to the same difference (but positive: (e.pageX - $currentHighlight.position().left) * -1 ).