JS`array.sort`在IE6中失败，因为它的比较值不是数字。 怎么解决？

Question

I have the following sort function which attempts to sort the items based on whether they start with a value entered into a text box.

items.sort(function(a, b) {
    var aStart = a.name.match(new RegExp('^' + textEntered, 'i')) || [];
    var bStart = b.name.match(new RegExp('^' + textEntered, 'i')) || [];

    if (aStart.length != bStart.length) {
        return bStart.length - aStart.length;
    }
    else {
        return b.name - a.name; // error because these aren't numbers
    }

    return 0;
});

This works in every browser I've tried it in, except for IE6, which returns an error stating that it expected a number.

I tried to implement the suggested fix from this article, which suggests "Don't reuse the argument variables inside of an Array sort function.": http://www.zachleat.com/web/array-sort with the following:

items.sort(function(a1, b1) {

    var a, b;
    a = a1;
    b = b1;

    var aStart = a.name.match(new RegExp('^' + textEntered, 'i')) || [];
    var bStart = b.name.match(new RegExp('^' + textEntered, 'i')) || [];

    if (aStart.length != bStart.length) {
        return bStart.length - aStart.length;
    }
    else {
        return b.name - a.name;
    }

    return 0;
});

but it doesn't have any effect. Has anyone had to deal with this before? What's the best fix for this issue?

Answer 1

如果你想字符串之间的比较，并希望返回-1 ， 0或1 ，使用localeCompare()

return a.name.localeCompare(b.name);