C＃获取在openfile对话框中打开的文件的文件名

Question

Is there a way to get the file name of a file you open using the openfiledialog in C#? I need this because, the user is going to open an image file, but then the image file is added to a listbox(using its filename), then can be selected for display in a picturebox. Having trouble finding a solution for this. Cheers.

Answer 1

Use OpenFileDialog.FileName :

if(openFileDialog.ShowDialog() == DialogResult.OK)
{
    InsertIntoList(openFileDialog.FileName);
}

Answer 2

use openFileDialog.SafeFileName to get just the name of the file

openFileDialog.FileName returns the full path to the file

Answer 3

您是否尝试过使用openfiledialog.FileName属性？