使用数组中的PHP变量将其插入SQL数据库。 （语法错误）

Question

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING

Here's the line throwing the error.

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES($arr['title_id'], $arr['title'], $arr['year'])");    

Answer 1

You'll have to surround your variables in curly braces:

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES({$arr['title_id']}, {$arr['title']}, {$arr['year']})");

Take a look at my complex (curly) braces explanation here: Problem escaping php variable

Answer 2

The code that worked for me is as follows:

$result = mysql_query("
INSERT INTO movies (id, title, year) 
VALUES(" . implode($arr,', ').";

Using implode you get all the items on the array, using the ' , ' as separation character.

Answer 3

您应该阅读有关字符串的PHP文档，以了解代码错误的原因。

Answer 4

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES($arr['title_id'], $arr['title'], $arr['year'])"); 

我会这样：

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES(" . $arr['title_id']. ", " . $arr['title'] . ", " . $arr['year'] . ")"); 

Answer 5

As others have mentioned, you should use curly braces, or string concatenation using the . operator to embed the variables in your string.

Additionally, assuming that the title column is a VARCHAR field and the other two are INT fields, you have to put quotes around the title value:

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES(" . $arr['title_id'] . ", '" . $arr['title'] . "', " . $arr['year'] . ")");

You would have to do the same for the id and year fields if they were also VARCHAR fields.

Answer 6

This is a string parsing problem. See the PHP documentation on variable parsing . The problem is that the index is written without quotes when using simple syntax (without curly braces).

You can either use curly braces around your variables:

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES({$arr['title_id']}, {$arr['title']}, {$arr['year']})");

Or you can concatenate strings and variables together with dots, avoiding string parsing altogether:

$result = mysql_query('INSERT INTO movies (id, title, year) VALUES('.$arr['title_id'].', '.$arr['title'].', '.$arr['year'].')');

Or leave out the quotes, but this doesn't look too clean:

$result = mysql_query("INSERT INTO movies (id, title, year) VALUES($arr[title_id], $arr[title], $arr[year])");

Answer 7

Not a direct answer, but I'd highly recommend moving to PHP Data Objects if possible. Supports many of the higher level mysql functions like prepared statements (no more worries of sql injection), pulling data directly into objects, etc.