Javascript 正则表达式只接受字母、空格和 ñ

Question

I am looking for a Javascript regex to make sure the string contains only spaces, letters, and ñ — case insensitively.

I already tried: /^[A-Za-z _]*[A-Za-z][A-Za-z _]*$/ but it fails to accept ñ .

Answer 1

/^[ñA-Za-z _]*[ñA-Za-z][ñA-Za-z _]*$/

and

/^[\u00F1A-Za-z _]*[\u00F1A-Za-z][\u00F1A-Za-z _]*$/

should work.

Javascript regex supports \ through \￿ .

Answer 2

If you simply want that caracter, insert it in the Regex, like [A-Za-zÑñ ] . Otherwise use a Unicode-knowing Regex library for Javascript like http://xregexp.com/ . Sadly JS Regexes don't support Unicode compliant character classes (like \\p{L} in C# regexes)

Answer 3

您需要使用字符类。

/[A-Za-z ñ]+/

Answer 4

This worked out for me /^[a-zA-ZáéñóúüÁÉÑÓÚÜ -]*$/ a shorter version from @tchris t answer ^^

Answer 5

这对我有用，允许使用 ñóíú 和空格等 utf8 字符

const validationsLetters = /^[a-zA-Z\u00C0-\u00FF ]*$/;

Answer 6

With this it forces not to have spaces at the beginning but if later

/^[a-zA-Z\u00C0-\u00FF][a-zA-Z\u00C0-\u00FF\s]*$/

..for email you can use:

/^[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}$/i

..for password you can use:

/^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{6,}$/i

I hope it works for you like it did for me, good look..!