如何使用相对路径调用另一个 PowerShell 脚本？

Question

I have the following directory tree:

e:\powershell\services\This-Script-Here-Should-Call-Press any key to continue.ps1
e:\powershell\utils\Press any key to continue.ps1

and now I'd like to call a script named "Press any key to continue.ps1" that sits in the "utils"-folder from a script that I have in the "services"-folder. How do I do that? I cannot figure out the relative path.

I tried to do it this way:

"$ '.\..\utils\Press any key to continue.ps1'"

but it did not work.

Answer 1

Based on what you were doing, the following should work:

& "..\utils\Press any key to continue.ps1"

or

. "..\utils\Press any key to continue.ps1"

(lookup the difference between using & and . and decide which one to use)

This is how I handle such situations ( and slight variation to what @Shay mentioned):

$scriptDir = Split-Path -Parent $MyInvocation.MyCommand.Path
$utilsDir  = Join-Path -Path $scriptDir -ChildPath ..\utils

& "$utilsDir\Press any key to continue.ps1"

Answer 2

Put the following function in the calling script to get its directory path and join the utils path along with the script name:

# create this function in the calling script
function Get-ScriptDirectory { Split-Path $MyInvocation.ScriptName }

# generate the path to the script in the utils directory:
$script = Join-Path (Get-ScriptDirectory) 'utils\Press any key to continue.ps1'

# execute the script
& $script 

Answer 3

To get the current script path $PSScriptRoot variable can be used. for example Following is the structure: solution\\mainscript.ps1 solution\\secondscriptfolder\\secondscript.ps1

#mainscript.ps1

$Second = Join-Path $PSScriptRoot '\secondscriptfolder\secondscript.ps1'

$Second

Answer 4

Thank you very informative. I had similar issue, I could get it work like this, to call other scripts from parentfolder.

$CommandPath = (Get-Location).Path | Split-Path -Parent; $script = "$CommandPath\Logins\Login_SSI_SST_exch2010_DKSUND_Exchange365.ps1"; & $script