从python启动新shell窗口中的程序

Question

I am trying to launch a python script from another python script in a new shell window. So far I'm unable to do it. Does anyone knows how can I accomplish this?

for example

import subprocess
process = subprocess.Popen('test.py', shell=True, stdout=subprocess.PIPE)
process.wait()
print (process.returncode)

when I'll run this script, it should launch 'test.py' in a new a new shell window.

I'm using linux, but it will be very helpful if you can provide solution for windows too.

Answer 1

Here's how you could do it on Debian-like systems:

import subprocess
import shlex
process = subprocess.Popen(
    shlex.split("""x-terminal-emulator -e 'bash -c "test.py"'"""), stdout=subprocess.PIPE)
process.wait()
print (process.returncode)

Something like it should work for any *nix system.

Many thanks to eudoxos for pointing out x-terminal-emulator !

Answer 2

Instead of launching a shell, launch a terminal running your script. On Linux, xterm -e test.py ; the Windows equivalent would be cmd.exe test.py I believe (but I could be wrong).