[英]Dynamic Play! template links
I"m having trouble generating dynamic links from strings. I have a controller which renders a page: 我无法从字符串生成动态链接。我有一个呈现页面的控制器:
public class ViewController extends Controller {
public static void index() {
Map<String, String> breadcrumbsMap = new LinkedHashMap<String, String>();
breadcrumbsMap.put("Home", "ViewController.index()");
breadcrumbsMap.put("User", "UserController.index()");
render(breadcrumbsMap);
}
}
The page has markup that looks like (but doesn't work): 该页面具有如下标记(但不起作用):
<ul id="breadcrumbs">
#{list items:breadcrumbsMap.keySet(), as:'key'}
<li>#{a @breadcrumbsMap.get(key)}${key}#{/a}</li>
#{/list}
</ul>
I can't figure out how to make the markup turn the string into a link. 我不知道如何使标记将字符串转换为链接。 From the docs, something standard would be: 从文档中,一些标准是:
#{a @Application.logout()}Disconnect#{/a}
<a href="breadcrumbsMap.get(key)">&{key}</a>
Try 尝试
breadcrumbsMap.put("Home", Router.reverse("ViewController.index()", emptyMap).url);
breadcrumbsMap.put("User", Router.reverse("UserController.index()", emptyMap).url);
And display the link like any string: 并像显示任何字符串一样显示链接:
<a href="breadcrumbsMap.get(key)">${key}</a>
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