[英]How can I limit the number of digits displayed by printf after the decimal point?
I wrote a small program that reads two integers using scanf
and then performs various arithmetic calculations.我写了一个小程序,它使用
scanf
读取两个整数,然后执行各种算术计算。 I'm using printf
to display the results.我正在使用
printf
来显示结果。 How can I make printf
display only two digits after the decimal point?如何让
printf
只显示小数点后两位? Starting with the simplified code sample:从简化的代码示例开始:
#include <stdio.h>
int main(void)
{
double third = 1.0 / 3.0;
// display data
printf("\n%20s%20s", "Description", "Data");
printf("\n%20s%20s", "-----------", "----");
printf("\n%20s%20lf", "One third", third);
printf("\n");
return 0;
}
This prints "0.333333" for the value of third
.这将打印“0.333333”作为
third
值。 How would I alter the above to get the following output?我将如何更改上述内容以获得以下输出?
\n Description Data描述数据\n ----------- ----
----------- ----\n One third 0.33
三分之一 0.33\n
use "%.2f" at the place you want.在你想要的地方使用“%.2f”。
For example, modify the following statement比如修改下面的语句
printf("\n%20s%20lf", "Fraction", quotientdecimal);
into this one :进入这个:
printf("\n%20s%.2f", "Fraction", quotientdecimal);
will only display two fraction numbers of the variable quotlentdecimal.将只显示变量 quotlentdecimal 的两个小数。
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