mysql事务 - 混合插入和选择以获得last_insert_id？

Question

I'm performing a transaction (using PDO), however I need to grab the insert id of the first element in the transaction, for example:

BEGIN
INSERT INTO user (field1,field2) values (value1,value2)
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
COMMIT;

Then do the pdo stuff:

[...]
$pdo->execute();
$foo = $pdo->lastInsertId(); // This needs to be the id from the FIRST insert

Is there a way to get the last insert id from the first element in a transaction? Perhaps using something like the following:

BEGIN
INSERT INTO user (field1,field2) values (value1,value2)
SELECT id AS user_id FROM user WHERE id=LAST_INSERT_ID()
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
COMMIT;

$pdo->execute();
$fooArray = $pdo->fetchAll();
$lastId = $fooArray[0]['user_id'];

Am I completely out to lunch with ^ ? Is there a better way to do this?

EDIT 1

Based on suggestion, i've updated the query to use variables... however, i don't know how to retrieve the variable values using PDO. Using $stmt->fetchAll() just returns an empty array;

BEGIN
DECLARE User_ID int
DECLARE Option_ID int
INSERT INTO user (field1,field2) values (value1,value2);
set User_ID = select LAST_INSERT_ID();
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
set Option_ID = select LAST_INSERT_ID();
select User_ID, Option_ID
COMMIT;

Answer 1

You can do it this way, put the value into variable then just select it

BEGIN
DECLARE User_ID int
DECLARE Option_ID int
INSERT INTO user (field1,field2) values (value1,value2);
set User_ID = select LAST_INSERT_ID();
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
set Option_ID = select LAST_INSERT_ID();
select User_ID, Option_ID
COMMIT;