[英]How to set all bits of enum flag
I wonder a generic way for setting all bits of enum
flag to 1. I just would like to have an enum
which returns for all comparisons, regardless of other enums.我想知道将
enum
标志的所有位设置为 1 的通用方法。我只想有一个enum
,它返回所有比较,而不考虑其他枚举。
And this code works;这段代码有效;
[Flags]
public enum SomeRightEnum : uint
{
CanDoNothing = 0,
CanDoSomething = 1 << 0,
CanDoSomethingElse = 1 << 1,
CanDoYetAnotherThing = 1 << 2,
...
DoEverything = 0xFFFFFFFF
}
But at the code above since it is uint we set the number of "F"s, it wouldn't work if it was int
.但是在上面的代码中,因为它是 uint 我们设置了“F”的数量,如果它是
int
它将不起作用。
So I'll appreciate a generic way of setting all bits of enum
flag to 1, regardless of the datatype ( i
nt, int64
, uint
etc)因此,无论数据类型如何(
i
nt、 int64
、 uint
等),我都会欣赏将enum
标志的所有位设置为 1 的通用方法
Easiest is probably: 最简单的可能是:
enum Foo
{
blah = 1,
....
all = ~0
}
For unsigned based enum: 对于基于unsigned的枚举:
enum Foo : uint
{
blah = 1,
....
all = ~0u;
}
[Flags]
public enum MyEnum
{
None = 0,
First = 1 << 0,
Second = 1 << 1,
Third = 1 << 2,
Fourth = 1 << 3,
All = ~(-1 << 4)
}
internal static class Program
{
private static void Main()
{
Console.WriteLine(Foo.Everything.HasFlag(Foo.None)); // False
Console.WriteLine(Foo.Everything.HasFlag(Foo.Baz)); // True
Console.WriteLine(Foo.Everything.HasFlag(Foo.Hello)); // True
}
}
[Flags]
public enum Foo : uint
{
None = 1 << 0,
Bar = 1 << 1,
Baz = 1 << 2,
Qux = 1 << 3,
Hello = 1 << 4,
World = 1 << 5,
Everything = Bar | Baz | Qux | Hello | World
}
Was this what you wanted? 这是你想要的吗?
In case someone is wondering: I needed to do the same building a Bindable enumconverter for WPF. 如果有人想知道:我需要为WPF构建一个Bindable enumconverter。
Since I don't know what the values mean in Reflection, I needed to manually been able to switch values (binding them to a checkbox pe) 由于我不知道反射中值的含义,我需要手动切换值(将它们绑定到复选框pe)
There is a problem setting the value of a Flagged enum to -1 to set all the bits. 将Flagged枚举的值设置为-1以设置所有位时出现问题。
If you set it to -1 and you unflag all values it will not result in 0 because all unused bits are not unflagged. 如果将其设置为-1并且取消标记所有值,则不会导致0,因为所有未使用的位都不会被标记。
This is wat worked best for my situation. 这对我的情况最好。
SomeRightEnum someRightEnum = SomeRightEnum.CanDoNothing;
Type enumType = someRightEnum.GetType();
int newValue = 0;
var enumValues = Enum.GetValues(enumType).Cast<int>().Where(e => e == 1 || e % 2 == 0);
foreach (var value in enumValues)
{
newValue |= value;
}
Console.WriteLine(newValue);
Or if you would want an extension method: 或者,如果您需要扩展方法:
public static class FlagExtensions
{
public static TEnum AllFlags<TEnum>(this TEnum @enum)
where TEnum : struct
{
Type enumType = typeof(TEnum);
long newValue = 0;
var enumValues = Enum.GetValues(enumType);
foreach (var value in enumValues)
{
long v = (long)Convert.ChangeType(value, TypeCode.Int64);
if(v == 1 || v % 2 == 0)
{
newValue |= v;
}
}
return (TEnum)Enum.ToObject(enumType , newValue);
}
}
I find All = ~0
more elegant, but to have more transparency starting from C# 7.0 you can use我发现
All = ~0
更优雅,但从C# 7.0开始,您可以使用更多的透明度
binary literals like 0b0101010111
together with digit separators _
like 0b_0101_0101_11
.像
0b_0101_0101_11
这样的二进制文字和数字分隔符_
像0b0101010111
。
So to set all flags for the Int32
you can chose one of the following possibilities, all of them are the same:因此,要为
Int32
设置所有标志,您可以选择以下可能性之一,它们都是相同的:
All = unchecked((int)0b_1111_1111_1111_1111_1111_1111_1111_1111)
All = unchecked((int)0b_11111111_11111111_11111111_11111111)
All = unchecked((int)0b11111111111111111111111111111111)
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