如何使用GAE获取上传文件的文件名？
[英]How can I get the filename of an uploaded file with GAE?
问题描述
I just upload it to the db (coming from a user request) like this: 
我只是将它上传到db（来自用户请求），如下所示：
x.file = db.Blob(self.request.get("img"))
How do I get the filename, I have both the request and the blob, any solution that could be applied for any of them is ok for me 我如何获取文件名，我有请求和blob，任何可以应用于任何一个的解决方案对我来说都没问题
2 个解决方案
解决方案1
2 2011-09-20 20:40:31
The object that is returned by self.request.get("img") will have a property called filename . self.request.get("img")返回的对象将具有名为filename的属性。 Assuming that "img" is a file upload, of course. 当然，假设“img”是文件上传。
解决方案2
0 2011-09-20 16:24:00
您必须使用BlobstoreUploadHandler返回的BlobInfo，如http://code.google.com/appengine/docs/python/tools/webapp/blobstorehandlers.html所述，它具有文件名属性，如此处所述http://code.google的.com /应用服务引擎/文档/蟒/ Blob存储区/ blobinfoclass.html
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