[英]Need to escape non-ASCII characters in JavaScript
Is there any function to do the following? 是否有任何功能可以执行以下操作?
var specialStr = 'ipsum áá éé lore';
var encodedStr = someFunction(specialStr);
// then encodedStr should be like 'ipsum \u00E1\u00E1 \u00E9\u00E9 lore'
I need to encode the characters that are out of ASCII range, and need to do it with that encoding. 我需要编码超出ASCII范围的字符,并需要使用该编码。 I don't know its name.
我不知道它的名字。 Is it Unicode maybe?
它可能是Unicode吗?
This should do the trick: 这应该做的伎俩:
function padWithLeadingZeros(string) {
return new Array(5 - string.length).join("0") + string;
}
function unicodeCharEscape(charCode) {
return "\\u" + padWithLeadingZeros(charCode.toString(16));
}
function unicodeEscape(string) {
return string.split("")
.map(function (char) {
var charCode = char.charCodeAt(0);
return charCode > 127 ? unicodeCharEscape(charCode) : char;
})
.join("");
}
For example: 例如:
var specialStr = 'ipsum áá éé lore';
var encodedStr = unicodeEscape(specialStr);
assert.equal("ipsum \\u00e1\\u00e1 \\u00e9\\u00e9 lore", encodedStr);
Just for information you can do as Domenic said or use the escape
function but that will generate unicode with a different format (more browser friendly): 只是为了获取您可以做的信息,如Domenic所说或使用
escape
函数,但这将生成具有不同格式的unicode(更适合浏览器):
>>> escape("áéíóú");
"%E1%E9%ED%F3%FA"
If you need hex encoding rather than unicode then you can simplify @Domenic's answer to: 如果您需要十六进制编码而不是unicode,那么您可以简化@ Domenic的答案:
"aäßåfu".replace(/./g, function(c){return c.charCodeAt(0)<128?c:"\\x"+c.charCodeAt(0).toString(16)})
returns: "a\xe4\xdf\xe5fu"
This works for me. 这适合我。 Specifically when using the Dropbox REST API:
特别是在使用Dropbox REST API时:
encodeNonAsciiCharacters(value: string) {
let out = ""
for (let i = 0; i < value.length; i++) {
const ch = value.charAt(i);
let chn = ch.charCodeAt(0);
if (chn <= 127) out += ch;
else {
let hex = chn.toString(16);
if (hex.length < 4)
hex = "000".substring(hex.length - 1) + hex;
out += "\\u" + hex;
}
}
return out;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.