[英]How to update an XML column with value from T-SQL built-in function?
I have a MS SQL 2008 R2 Standard database. 我有一个MS SQL 2008 R2标准数据库。 I have a column with varchar(250)
data and a column with xml
. 我有一个包含varchar(250)
数据的列和一个包含xml
的列。
CREATE TABLE [dbo].[art](
[id] [int] IDENTITY(1,1) NOT NULL,
[idstr] [varchar](250) NULL,
[rest] [xml] NOT NULL,
CONSTRAINT [PK_art] PRIMARY KEY CLUSTERED ([id] ASC)
)
The problem is I want to insert result of a string function into into xml, in about 140 records. 问题是我想在大约140条记录中将字符串函数的结果插入到xml中。 I've tried to use xml.modify
with dynamically generated text. 我试图使用动态生成的文本xml.modify
。
UPDATE [pwi_new].[dbo].[art]
SET rest.modify('insert <e><k>link</k><v>'
+ my_string_function(idstr) + '</v></e> into (/root)[1]')
WHERE parent = 160
AND idstr LIKE '%&%'
GO
However, I've got this error: 但是,我有这个错误:
The argument 1 of the XML data type method "modify" must be a string literal.
Any ideas? 有任何想法吗? I'd like to avoid using temporal fields, external languages and executing TSQL from generated string? 我想避免使用时态字段,外部语言和从生成的字符串执行TSQL? (I've heard of sql:variable
and sql:column
, but this is a result of tsql function.) (我听说过sql:variable
和sql:column
,但这是tsql函数的结果。)
Not sure what you want to do here. 不知道你想在这做什么。 You mention a TSQL function and if that is the replace & to & it is not necessary. 你提到了一个TSQL函数,如果那是替换&to,则没有必要。 It is taken care of by SQL Server for you. 它由SQL Server为您处理。
A test using a table variable @art
: 使用表变量@art
测试:
declare @art table(parent int, idstr varchar(250), rest xml)
insert into @art values
(160, '123&456', '<root></root>')
update @art
set rest.modify('insert (<e><k>link</k><v>{sql:column("idstr")}</v></e>) into (/root)[1]')
where parent = 160 and
idstr like '%&%'
select rest
from @art
Result: 结果:
<root>
<e>
<k>link</k>
<v>123&456</v>
</e>
</root>
Update 更新
For the not so trivial situations you can use a cross apply to get the values you need into a column. 对于不那么微不足道的情况,您可以使用交叉应用将所需的值添加到列中。
declare @art table(parent int, idstr varchar(250), rest xml)
insert into @art values
(160, '123&456', '<root></root>')
update a
set rest.modify('insert (<e><k>link</k><v>{sql:column("T.X")}</v></e>) into (/root)[1]')
from @art as a
cross apply (select reverse(replace(idstr, '2', '8')+'NotSoTrivial')) as T(X)
where parent = 160 and
idstr like '%&%'
select rest
from @art
Result: 结果:
<root>
<e>
<k>link</k>
<v>laivirToStoN654&381</v>
</e>
</root>
Assuming your table has a key: 假设你的桌子有一把钥匙:
DECLARE @sql NVARCHAR(MAX) = N'';
SELECT @sql += CHAR(13) + CHAR(10) + 'UPDATE [pwi_new].[dbo].[art] '
+ ' SET rest.modify(''insert <e><k>link</k><v>'
+ REPLACE(idstr,'&','&')
+ '</v></e> into (/root)[1]'') WHERE key_column = '
+ CONVERT(VARCHAR(12), key_column) + ';'
FROM [pwi_new].[dbo].[art]
WHERE parent = 160
AND idstr LIKE '%&%';
PRINT @sql;
--EXEC sp_executesql @sql;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.