如何为c写一个简单的makefile

Question

I need to write a simple make file for my.c, and so after

make

then my program can be run by

./my

my.c can be compiled by this:

gcc cJ/cJ.c my.c -lcrypto -o my -lm

Thanks I put this in my makefile

all:my
my: cJ.o my.o
 gcc cJ.o -lcrypt my.o -o my
cJ.o: cJ/cJ.c
     gcc -c cJ/cJ.c
my.o: my.c
     gcc -c my.c -lm

help please

Answer 1

Here it a simple tutorial you could follow: http://www.cs.colby.edu/maxwell/courses/tutorials/maketutor/

One very important thing with make is to get the tabs right!

Answer 2

Well, makefiles are just kind of special scripts. Every is unique, for such simple task this would be sufficient:

Makefile:

CC=gcc
CFLAGS=-lm -lcrypto
SOURCES=my.c cJ/cJ.c

all: my

my: $(SOURCES)
        $(CC) -o my $(SOURCES) $(CFLAGS)

Later you may want to use some other options such as wildcards %.c to compile in multiple files without having to write them in.

Alternatively:

CC=gcc
CFLAGS=-lm -lcrypto

MY_SOURCES = my.c cJ/cJ.c
MY_OBJS = $(patsubst %.c,%.o, $(MY_SOURCES))

all: my

%o: %.c
    $(CC) $(CFLAGS) -c $<

my: $(MY_OBJS)
    $(CC) $(CFLAGS) $^ -o $@

Note that lines following each target ("my:", ...) must start with tab (\\t), not spaces.

Answer 3

Just a minor correction: put the -lm to the linking step, and there after all object files.

all: my
my: cJ.o my.o
    gcc cJ.o my.o -o my -lcrypt -lm
cJ.o: cJ/cJ.c
    gcc -c cJ/cJ.c
my.o: my.c
    gcc -c my.c

And then, you could work more with automatic variables :

all: my
my: cJ.o my.o
    gcc $^ -o $@ -lcrypt -lm
cJ.o: cJ/cJ.c
    gcc -c $^
my.o: my.c
    gcc -c $^

where $@ is the target of the current rule and $^ are the prerequisites.

See also http://www.gnu.org/software/make/manual/make.html .

Answer 4

simple make file for your program is

build : 
        gcc /your_full_path_to_c_file/cJ.c my.c -lcrypto -o my -lm

just copy this in one file keep name of that file as makefile then run as make build