如何打印出 Linux 内核中的寄存器？

Question

I want to print out values of a couple of registers from the linux kernel code running on ARM. Particularly I have the following assembly in linux -

e3c52007        bic     r2, r5, #7      ; 0x7
e1520003        cmp     r2, r3
0a000003        beq     c011fa60 <smem_find+0x40>

How do I print out the values of r2, r3 and r5 in kmsg? I do not want to use the variable names and want to get the values from registers.

Answer 1

I'm not that familiar with kernel development and easy ways to debug, but this would do the job I guess.

size_t r2, r3, r5;

asm ("str r2, %[r2]\n"
     "str r3, %[r3]\n"
     "str r5, %[r5]\n"
 : [r2]"=m" (r2), [r3]"=m" (r3), [r5]"=m" (r5));
 printk("r2=%u r3=%u r4=%u\n", r2, r3, r5);

Edit: Now with ARM assembly instead of x86 :p

Answer 2

You can call show_regs(struct pt_regs * regs) . This function will diplay all the registrs on the pt_regs structure.