[英]Find Duplicates using Rank Over Partition
The following SQL works in identifying unique phones when there is a disparity in LastDate. 以下SQL用于在LastDate中存在差异时识别唯一的电话。 But if duplicate phones have the exact same LastDate it does not work. 但是,如果重复的手机具有完全相同的LastDate,则它不起作用。
Any ideas will be appreciate it. 任何想法都会欣赏它。
SELECT * FROM
(
SELECT ID, Phone, [LastDate]
,RANK() OVER (PARTITION BY Phone ORDER BY [LastDate]) AS 'RANK',
COUNT(Phone) OVER (PARTITION BY Phone) AS 'MAXCOUNT'
FROM MyTable
WHERE Groupid = 5
) a
WHERE [RANK] = [MAXCOUNT]
Change the RANK
for ROW_NUMBER
. 更改ROW_NUMBER
的RANK
。
SELECT *
FROM ( SELECT ID, Phone, [LastDate],
ROW_NUMBER() OVER (PARTITION BY Phone ORDER BY [LastDate]) AS 'RANK',
COUNT(Phone) OVER (PARTITION BY Phone) AS 'MAXCOUNT'
FROM MyTable
WHERE Groupid = 5) a
WHERE [RANK] = [MAXCOUNT]
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