[英]Subtract SQL DATETIME from datetime.now() in Python
I have a DATETIME field in SQL. 我在SQL中有一个DATETIME字段。 Its content is: 2012-08-26 13:00:00
其内容是:2012-08-26 13:00:00
I want to know how much time has passed from that date until now. 我想知道从那个日期到现在已经过了多少时间。
In Python 2.7, it's easy: 在Python 2.7中,它很简单:
import time,datetime
start = datetime.datetime.strptime('2012-08-26 13:00:00', '%Y-%m-%d %H:%M:%S')
end = datetime.datetime.now()
delta = start - end
print delta
But I have a web server running Python 2.4. 但我有一个运行Python 2.4的Web服务器。 In Python 2.4 strptime is not in the datetime module.
在Python 2.4中,strptime不在datetime模块中。 I can't figure out how to accomplish the same thing in 2.4.
我无法弄清楚如何在2.4中完成同样的事情。
time.strptime is in Python 2.4. time.strptime在Python 2.4中。 It returns a time tuple, which can be then converted to a datetime as shown below.
它返回一个时间元组,然后可以将其转换为日期时间,如下所示。
start = time.strptime('2012-08-26 13:00:00', '%Y-%m-%d %H:%M:%S')
start = datetime.datetime(*start[:6])
在python 2.4中, strptime()
函数位于time
模块中。
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