从这样的网址加载xml数据：/index.php/site/projects/作为php变量

Question

I need to read xml data generated by a php file(of Expression Engine) on passing url like /index.php/site/projects/ into a php object. ( note that it is not a physical file ). How can I do that ?

Since I am not quite aware of php stuff please pardon me in case I have asked something silly & let me know in case I can add more information.

Answer 1

Perhaps you could use SimpleXML , the DOMDocument class, or cURL .

Edit:

An example taken from the documentation of simplexml_load_file

<?php
// The file test.xml contains an XML document with a root element
// and at least an element /[root]/title.

if (file_exists('http://domain.com/index.php/site/projects/')) {
    $xml = simplexml_load_file('http://domain.com/index.php/site/projects/');

    print_r($xml);
} else {
    exit('Failed to open the xml file.');
}
?>

I'm not an expert on this, but there are lots of good hints, examples, and notes on the page I linked to.

Answer 2

You can use simplexml_load_file(string $filename) to this end. Just pass into this function the full URL such as:

$myXMLContent = simplexml_load_file('http://myserver.com/index.php/site/projects/');

Then if you need to use this information, note that all nodes that are not repetitive will be accessible directly using:

$myXMLContent->nodename

Then all attributes are part of an array of the node, so:

<nodename id="6" name="blabla"><subnode>Content</subnode></nodename>

Can be fetched as:

echo $myXMLContent['id'];
echo $myXMLContent['name'];
echo $myXMLContent->subnode;

And if you have many subnodes at once, you can use:

echo $myXMLContent->subnode[2]

To get the 3rd subnode.

This is the best i can do to help you, the rest can be found at: http://www.php.net/manual/fr/book.simplexml.php