[英]mysql: exact match?
I'm pulling some data from mysql and counting occurrences of matches (seemingly equivalent to WHERE foo='bar'
). 我从mysql中提取了一些数据并计算了匹配项的出现(似乎等同于
WHERE foo='bar'
)。 However, as I loop thru the data in PHP, my count is much lower than the count in mysql. 但是,当我遍历PHP中的数据时,我的计数比mysql中的计数低得多。
MYSQL> SELECT COUNT(foo) FROM database.table WHERE foo='bar';
# PHP
while ($response = mysql_fetch_assoc($surveydata)){
if ($response==='bar') {
$bar++;
}
}
The data might contain one or more &
, so I want to match only bar
and not bar & foobar
. 数据可能包含一个或多个
&
,因此我只想匹配bar
而不匹配bar & foobar
。 I suspect mysql is counting bar
and bar & foobar
whereas php is only counting bar
and not bar & foobar
. 我怀疑mysql正在计数
bar
和bar & foobar
而php仅计数bar
而不是bar & foobar
。 Php is returning 1210
, and mysql is returning 1783
, so it's exactly practical to manually count to see who is right… Php返回
1210
,而mysql返回1783
,因此手动计数以查看谁是正确的是完全可行的……
I googled around, but was surprised nothing relevant came up for "mysql exact match" or "mysql exactly equal" x,x 我四处搜寻,但感到惊讶的是,“ mysql完全匹配”或“ mysql完全相等”没有相关的信息x,x
here's the actual sql 这是实际的SQL
SELECT COUNT(`race`) FROM `database`.`table` WHERE `completion status`='complete';
and the actual php 和实际的PHP
mysql_query("SELECT `race`,`etcetera` FROM `database`.`table` WHERE `completion status`='complete';");
$demographics=array(
"race"=>array(
"White"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Black"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Hispanic"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Asian"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Pacific Islander"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Multiracial"=>array('consented'=>0,'partial'=>0,'completed'=>0),
"Other"=>array('consented'=>0,'partial'=>0,'completed'=>0)
)
//more
);
while ($dbrecord = mysql_fetch_assoc($surveydata)) {
foreach ( $dbrecord as $dbfield=>$dbcellval ) {
foreach ( $demographics as $demographic=>&$options ) {
foreach ( $options as $option=>&$counter ) {
if ( $option==="Multiracial" && strpos($dbcellval,'&') >0 && strpos($dbcellval,'&')!==false ) {
if ($dbrecord['consent']==="1"){
$demographics["race"]["Multiracial"]['consented']++;
if ($dbrecord['completion status']==="partial") {
$demographics["race"]["Multiracial"]['partial']++;
} // if
else if ($dbrecord['completion status']==="complete") {
$demographics["race"]["Multiracial"]['completed']++;
} // else if
} // if
}
else if ($option===$dbcellval){
if ($dbrecord['consent']==="1"){
$counter['consented']++;
if ($dbrecord['completion status']==="partial") {
$counter['partial']++;
} // if
else if ($dbrecord['completion status']==="complete") {
$counter['completed']++;
} // else if
} // if
} // else if $option==$item
} // foreach $options
} // foreach $demographics
} // foreach $dbrecord
} // while
the data from SELECT race FROM database.table
looks like: SELECT race FROM database.table
的数据如下所示:
White & Black
White
White & Asian
White & Asian & Black
Asian
Asian & Black
// etc
You can do this: 你可以这样做:
MYSQL> SELECT COUNT(foo) FROM database.table WHERE BINARY foo='bar';
BINARY does the magic!!! BINARY做魔术!!!
If you want to count the records where foo
is exactly bar
, your SQL query is correct. 如果要计算
foo
恰好是bar
的记录,则SQL查询是正确的。
There's something wrong with your PHP code and the code you posted shouldn't work at all (should count 0 records). 您的PHP代码出问题了,您发布的代码根本不起作用(应该记录0条记录)。
MYSQL> SELECT COUNT(foo) AS rows FROM database.table WHERE foo='bar'; MYSQL> SELECT COUNT(foo)作为来自database.table的行WHERE foo ='bar';
$response = mysql_fetch_assoc($surveydata);
echo $response['rows'];
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