我在python中使用time（）无法弄清楚这个错误

Question

Here is my code:

# Given an Unix timestamp in milliseconds (ts), return a human-readable date and time (hrdt)
def parseTS(ts):
  hrdt = time.strftime("%a, %d %b %Y %H:%M:%S +0000", time.time(int(ts)/1000))
  return str(hrdt)

I am getting this error:

TypeError: time() takes no arguments (1 given)

UPDATE:

This worked:

hrdt = datetime.datetime.fromtimestamp(int(ts)//1000)
return hrdt

Answer 1

The time.time(int(ts)/1000) function is wrong.

Try one of time.ctime, time.gtime() or time.localtime() functions to achieve what you want.

Python Docs (Time)

Answer 2

As the error says, time.time() doesn't take any arguments, it just returns current time as floating point. Maybe you are thinking of time.ctime()?

Answer 3

The problem is this:

time.time(int(ts)/1000)

And (as the error is telling you), time() takes no arguments .

It's unclear what you're trying to do, but maybe you want:

int(time.time() / 1000)

Or just int(time.time()) if you want the time in seconds without the floating point part.