将向量传递给函数c ++

Question

I have a main.cpp test.h and test.cpp> I am trying to pass my vector through so i can use it in test.cpp but i keep getting errors.

   //file: main.cpp
    int main(){
        vector <Item *> s;
         //loading my file and assign s[i]->name and s[i]-address
         tester(s);
    }

    //file: test.h
    #ifndef TEST_H
    #define TEST_H
    struct Item{
        string name;
        string address;
    };
    #endif

    //file: test.cpp
    int tester(Item *s[]){
        for (i=0; i<s.sizeof();i++){
            cout<< s[i]->name<<"  "<< s[i]->address<<endl;
        }
        return 0;
    }



    ---------------errors--------
    In file included from main.cpp:13:
    test.h:5: error: âstringâ does not name a type
    test.h:6: error: âstringâ does not name a type
    main.cpp: In function âint main()â:
    main.cpp:28: error: cannot convert âstd::vector<Item*, std::allocator<Item*> >â to âItem**â for argument â1â to âint tester(Item**)â

Answer 1

A std::vector<T> and T* [] are not compatible types.

Change your tester() function signature as follows:

//file: test.cpp
int tester(const std::vector<Item>& s)   // take a const-reference to the std::vector
                                         // since you don't need to change the values 
                                         // in this function
{
    for (size_t i = 0; i < s.size(); ++i){
        cout<< s[i]->name<<"  "<< s[i]->address<<endl;
    }
    return 0;
}

There are several ways you could pass this std::vector<T> and all have slightly different meanings:

// This would create a COPY of the vector
// that would be local to this function's scope
void tester(std::vector<Item*>); 

// This would use a reference to the vector
// this reference could be modified in the
// tester function
// This does NOT involve a second copy of the vector
void tester(std::vector<Item*>&);

// This would use a const-reference to the vector
// this reference could NOT be modified in the
// tester function
// This does NOT involve a second copy of the vector
void tester(const std::vector<Item*>&);

// This would use a pointer to the vector
// This does NOT involve a second copy of the vector
// caveat:  use of raw pointers can be dangerous and 
// should be avoided for non-trivial cases if possible
void tester(std::vector<Item*>*);

Answer 2

将其作为std::vector<Item *> & （引用向量）传递，并使用迭代器迭代它。

Answer 3

1. You should #include <string> .
2. string name should read std::string name etc. Same goes for std::vector .
3. You're calling tester() with a vector , yet it expects an array (the two are not interchangeable).
4. s.sizeof() is incorrect for both an array and a vector; for the latter, use s.size() or, better yet, use an iterator.

These are just the errors that immediately jump out; there may be more.

Answer 4

A vector is not an array.

int tester(vector<Item *> &s)

(pass as a reference to avoid copying or if you need to modify)

You also need to modify your code inside the tester function to work correctly as a vector.

Answer 5

You should fix

test.h:5: error: âstringâ does not name a type

first, probably by using namespace std; and #include <string>

Answer 6

You are missing includes

#include <string>
#include <vector>

and you need to use std::string and std::vector<> . A std::vector is not an array, so you should pass the vector as reference

int tester(std::vector<Item*> & vec) { //... }

or even as const std::vector<Item*> & if you are not going to modify the passed vector.

Also, are you sure, that you'll need a vector of pointers? What are you trying to achieve?