[英]How to compare two arrays and see if they have anything in common(PHP)
I need to compare two arrays and pass variable values according to the result. 我需要比较两个数组并根据结果传递变量值。 I loop $additionalTestsAvailable, if $additionalTestsSelected has a value in $additionalTestsSelected, passing 'Yes' to additionalTestsSelected, else passing ''.
如果$ additionalTestsSelected在$ additionalTestsSelected中有一个值,则将$ additionalTestsAvailable循环,将“是”传递给AdditionalTestsSelected,否则传递”。 But the result are all ''.
但结果全是''。 It shouldn't like this.
它不应该这样。 Anything wrong with my code?
我的代码有问题吗?
$additionalTestsSelected = $appointmentTime->getAdditionalTestsSelected();
$additionalTestsAvailable = $appointmentTime->getAdditionalTestsAvailable();
foreach($additionalTestsAvailable as $test) {
if(in_array($test,$additionalTestsSelected)){
$additionalTests[$test->getName()] = 'Yes';
}else{
$additionalTests[$test->getName()] = '';
}
}
I suspect your tests are coming out of the get functions as different objects even when they have the same name so the in_array
comparison is failing. 我怀疑您的测试是从get函数作为不同的对象发出的,即使它们具有相同的名称,因此
in_array
比较也失败了。 You can workaround this by looping manually and comparing the tests using their names: 您可以通过手动循环并使用测试名称进行比较来解决此问题:
foreach ($additionalTestsAvailable as $test) {
$result = '';
foreach ($additionalTestsSelected as $k) {
if ($test->getName() == $k->getName()) {
$result = 'Yes';
break;
}
}
$additionalTests[$test->getName()] = $result;
}
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