简体   繁体   English

C Unix / Linux编程:md_addr_t是哪种类型?

[英]C Unix/Linux programming: Which type is md_addr_t?

GCC gives me the following: GCC给我以下内容:

warning: passing argument 2 of ‘_panic’ discards qualifiers from pointer target type

misc.h:191: note: expected ‘char *’ but argument is of type ‘const char *’

The second argument is of type md_addr_t . 第二个参数的类型为md_addr_t How can I cast this to char* and what does md_addr_t meant to be? 我如何将其转换为char*以及md_addr_t是什么意思? (Neither man-page could help me nor google) (手册页都无法帮助我或Google)

The reason has been pointed out by larsmans correctly. 拉尔斯曼人已经正确指出了原因。 This warning is seen when casting const away ie if a function take non-const argument but you pass const argument, then if the function modifies the argument passed you have undefined behaviour. 强制转换const时会看到此警告,即如果函数采用non-const参数但您传递了const参数,那么如果函数修改了传递的参数,则您将具有未定义的行为。 md_addr_t which is typedef in the code has nothing to do with this. 在代码中为typedef的md_addr_t与此无关。 In the code you are getting these warning on using panic which is defined as follows (source from ss-ppc-little.tgz in your link): 在代码中,您收到有关使用panic警告,定义如下(来自链接中ss-ppc-little.tgz的信息):

#ifdef __GNUC__
/* declare a panic situation, dumps core */
#define panic(fmt, args...)     \
  _panic(__FILE__, __FUNCTION__, __LINE__, fmt, ## args)

void
_panic(char *file, char *func, int line, char *fmt, ...)
__attribute__ ((noreturn));
#else /* !__GNUC__ */
void 
panic(char *fmt, ...);
#endif /* !__GNUC__ */

On Unix/Linux system __GNUC__ is defined thus the first definition is used in which you are pre pending file name ( __FILE__ ), function name ( __FUNCTION__ ) & line number ( __LINE__ ) before printing out the message. 在Unix / Linux系统上,已定义__GNUC__ ,因此使用第一个定义,即在打印消息前先输入待处理的文件名( __FILE__ ),函数名( __FUNCTION__ )和行号( __LINE__ )。 (See this link for details).Here as you can see _panic expects char* as first & second arguments but arguments being passed are __FILE__ & __FUNCTION__ where __FUNCTION__ is static const char[] . (有关详细信息,请参_panic 链接 。)在这里,您可以看到_panic char*作为第一个和第二个参数,但是传递的参数是__FILE____FUNCTION__ ,其中__FUNCTION__static const char[] You can change _panic(char *file, char *func, int line, char *fmt, ...) to _panic(char *file, const char func[], int line, char *fmt, ...) or to _panic(char *file, const char *func, int line, char *fmt, ...) - as the compiler is complaining fix your warning. 您可以将_panic(char *file, char *func, int line, char *fmt, ...)更改为_panic(char *file, const char func[], int line, char *fmt, ...)_panic(char *file, const char *func, int line, char *fmt, ...) -编译器在抱怨修正您的警告。 As __FILE__ is also constant you can consider changing to _panic(const char *file, const char *func, int line, char *fmt, ...) 由于__FILE__也是常量,因此您可以考虑更改为_panic(const char *file, const char *func, int line, char *fmt, ...)
Hope this helps! 希望这可以帮助!

grep -R md_addr_t /usr/include does not return anything in a well-populated /usr/include , nor does it ring a bell. grep -R md_addr_t /usr/include在良好填充不返回任何/usr/include ,也不门铃。 It must be something in your application/library. 它必须在您的应用程序/库中。

In any case, casting to char * is just a matter of prefixing (char *) , which is also one of the few casts that are guaranteed to always work in C, although casting const away might mean that someone is going to write to read-only memory, which is not guaranteed to work... 在任何情况下,强制转换为char *都只是前缀(char *) ,这也是保证始终在C语言中正常工作的少数强制转换之一,尽管强制转换const可能意味着有人将要编写读写-仅内存,不能保证正常工作...

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM